If there is an excess of air, the reaction should produce diphosphorus pentoxide as its only product. If additionally the phosphorus molecule is simply a phosphorus atom, the balanced equation is: 4 P + 5 O2 -> 2P2O5. If phosphorus is considered to form a tetraatomic molecule, the equation would be:
P4 + 5 O2 -> 2 P2O5
The balanced chemical equation for burning C18H38 in air is: 2C18H38 + 55O2 → 36CO2 + 38H2O
C2H5OH +3O2 gives 2CO2 +3H2O ...it burns with ablue flame in air
Ca+O=CaO
This equation is C2H5OH + 3 O2 -> 2 CO2 + 3 H2O.
c12h26(i)--->c2h4(g)+______ Yuu shud work iht ouwt :)
The balanced chemical equation for burning C18H38 in air is: 2C18H38 + 55O2 → 36CO2 + 38H2O
The balanced chemical equation for methane (CH4) burning in air (O2) is: CH4 + 2O2 → CO2 + 2H2O
C2H5OH +3O2 gives 2CO2 +3H2O ...it burns with ablue flame in air
The balanced equation for the burning of carbon in air is: C + O2 -> CO2. This equation shows that one molecule of carbon reacts with two molecules of oxygen to produce one molecule of carbon dioxide.
The balanced equation for dimethylether (C2H6O) combusted in air is: 2 C2H6O + 5 O2 -> 4 CO2 + 6 H2O
The balanced equation for ethanol (C2H5OH) burned in air is: C2H5OH + 3O2 -> 2CO2 + 3H2O. This equation shows that ethanol reacts with oxygen to produce carbon dioxide and water.
The balanced equation for the complete oxidation of acetylene (C2H2) burning in air is: 2C2H2 + 5O2 -> 4CO2 + 2H2O. This equation shows that two molecules of acetylene react with five molecules of oxygen to produce four molecules of carbon dioxide and two molecules of water.
The word equation for a candle burning in the air is: Wax + Oxygen → Carbon Dioxide + Water + Light + Heat.
This equation is C2H5OH + 3 O2 -> 2 CO2 + 3 H2O.
Ca+O=CaO
c12h26(i)--->c2h4(g)+______ Yuu shud work iht ouwt :)
It reacts with the oxygen in the air. 2Mg + O2 ------> 2MgO Magnesium + Oxygen = Magnesium Oxide