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Masses: Mg= 24, S= 32, O= 16

Magnesium = 24g

Magnesium sulphate = (24+32)+(16x4) = 120g.

Therefor we know: 24g of Mg ----> makes 120g of MgSO4.

To get to 4g from 24g, you devide by 6.

(24 devided by 6 = 4g)

And to find what it would make, you devide 120 by 6 too.

Which = 20g.

4g of Mg ----> 20g of MgSO4.

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Can you calculate the number of moles of magnesium used grams permol?

To calculate the number of moles of magnesium used, you divide the mass of magnesium by its molar mass. The molar mass of magnesium is approximately 24.31 g/mol. For example, if you have 12.15 grams of magnesium, you would divide 12.15 by 24.31 to find that you have 0.5 moles of magnesium.


How many grams of magnesium oxide and oxygen react to form 20.0 grams of magnesium oxide?

To determine the amount of oxygen, we first find the amount of magnesium by subtracting the given 20.0 grams of magnesium oxide from the total. Given that the molar mass of magnesium oxide is 40.3 g/mol and that of magnesium is 24.3 g/mol, we calculate the amount of oxygen by adjusting accordingly. This process gives us the weight ratio of magnesium oxide to oxygen.


What mass of magnesium sulphate is needed to make 1500 ml of a 2.45 m mgso4 solution?

To find the mass of magnesium sulfate needed, first calculate the moles of MgSO4 required using the formula: moles = molarity × volume (in liters). Then, multiply the moles by the molar mass of MgSO4 (120.37 g/mol) to get the mass in grams. In this case, the mass of MgSO4 needed would be approximately 450.6 grams.


How many grams of magnesium would be required to produce 4.00 grams of magnesium oxide?

4.00 grams of magnesium oxide is composed of 2.43 grams of magnesium (Mg) and 1.57 grams of oxygen (O). Therefore, to produce 4.00 grams of magnesium oxide, you would need 2.43 grams of magnesium.


What is the largest mass of copper sulphate which can be dissolved in 50 grams of water at 60 degrees?

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Related Questions

Can you calculate the number of moles of magnesium used grams permol?

To calculate the number of moles of magnesium used, you divide the mass of magnesium by its molar mass. The molar mass of magnesium is approximately 24.31 g/mol. For example, if you have 12.15 grams of magnesium, you would divide 12.15 by 24.31 to find that you have 0.5 moles of magnesium.


How many grams of magnesium nitride can be made from 55.3 grams of magnesium if all the magnesium reacts only with nitrogen?

Balanced equation first. 3Mg + N2 -> Mg3N2 55.3 grams Mg (1 mole Mg/24.31 grams)(1 mole Mg3N2/3 mole Mg)(100.95 grams/1 mole Mg3N2) = 76.5 grams Mg3N2 made ===================


How many grams of magnesium oxide and oxygen react to form 20.0 grams of magnesium oxide?

To determine the amount of oxygen, we first find the amount of magnesium by subtracting the given 20.0 grams of magnesium oxide from the total. Given that the molar mass of magnesium oxide is 40.3 g/mol and that of magnesium is 24.3 g/mol, we calculate the amount of oxygen by adjusting accordingly. This process gives us the weight ratio of magnesium oxide to oxygen.


How many moles are in 400 grams of nickel sulphate?

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How many grams of magnesium would be required to produce 4.00 grams of magnesium oxide?

4.00 grams of magnesium oxide is composed of 2.43 grams of magnesium (Mg) and 1.57 grams of oxygen (O). Therefore, to produce 4.00 grams of magnesium oxide, you would need 2.43 grams of magnesium.


What mass of magnesium sulphate is needed to make 1500 ml of a 2.45 m mgso4 solution?

To find the mass of magnesium sulfate needed, first calculate the moles of MgSO4 required using the formula: moles = molarity × volume (in liters). Then, multiply the moles by the molar mass of MgSO4 (120.37 g/mol) to get the mass in grams. In this case, the mass of MgSO4 needed would be approximately 450.6 grams.


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2


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