Masses: Mg= 24, S= 32, O= 16
Magnesium = 24g
Magnesium sulphate = (24+32)+(16x4) = 120g.
Therefor we know: 24g of Mg ----> makes 120g of MgSO4.
To get to 4g from 24g, you devide by 6.
(24 devided by 6 = 4g)
And to find what it would make, you devide 120 by 6 too.
Which = 20g.
4g of Mg ----> 20g of MgSO4.
20g of MgSO
Yes
8 g of magnesium chloride is obtained.
340 grams
Radium sulphate (RaSO4) is very insoluble in water, more insoluble than the barium sulphate. The solubility product constant of radium sulphate is 3,66.10-11.
0.336g of anhydrous sodium sulphate
Magnesium chloride: 81,95 g are obtained.
Exactly 33,13035046 grams of copper.
Yes
8 g of magnesium chloride is obtained.
400 grams of nickel sulphate (anhydrous) is equivalent to 2,58 moles.
2
i dont know help :C
340 grams
calculate the percent yiel if 49 grams of PCL5 is obtained from the treatment of 33.9 grams of pcl5 with 19 grams cl2
Theoretically the mass is 62,3018 g.
871 grams
1,11 moles of magnesium have 26,97855 g.