When allowed to stand for long enough, the final temperature will reach room temperature.
To calculate the final temperature of the water, we need additional information such as the initial temperature of the second substance and their specific heat capacities. Without this information, we cannot provide an accurate answer.
The final temperature can be calculated using the principle of conservation of energy. The heat gained by the cooler water is equal to the heat lost by the warmer water. The final temperature is the temperature at which this heat exchange occurs, which can be calculated using the formula for heat transfer.
12 degrees Celsius
The saturated vapor pressure of water at 50 oC is 123,39 mm Hg.
To find the mass of 50 mL of water, you would multiply the volume of water (50 mL) by the density of water, which is about 1 gram per milliliter. Therefore, the mass of 50 mL of water would be approximately 50 grams.
To calculate the final temperature of the water, we need additional information such as the initial temperature of the second substance and their specific heat capacities. Without this information, we cannot provide an accurate answer.
To find the final temperature of the mixture, we can use the principle of conservation of energy, assuming no heat is lost to the surroundings. The heat gained by the cooler water (50 mL at 20°C) will equal the heat lost by the warmer water (200 mL at 70°C). The final temperature will be closer to the initial temperature of the warmer water due to its larger volume, likely resulting in a final temperature around 64-66°C.
The final temperature can be calculated using the principle of conservation of energy. The heat gained by the cooler water is equal to the heat lost by the warmer water. The final temperature is the temperature at which this heat exchange occurs, which can be calculated using the formula for heat transfer.
No, as both the temperatures are the same, you will get only 2 cups, each 50 degrees. You have to heat the cup to get 100 degree.
12 degrees Celsius
I believe it will be 145.52 degrees Celsius if I did my math correctly. You need to convert calories to joules. I believe one joule raises the temp of 1 gram water by 1 degree Celsius so 1200*4.184=5020.8 J /40grams=125.52 temp increase+20=145.52 degrees Celsius.
To calculate the BTUs needed to reduce the temperature of 50 gallons of water by 20°F, you can use the formula: BTU = gallons × weight of water (8.34 lbs/gallon) × temperature change (°F). For 50 gallons, that would be 50 × 8.34 × 20 = 8,340 BTUs. Therefore, you need approximately 8,340 BTUs to achieve this temperature reduction.
50 degrees.
The temperature can be 50 to 60 degrees. water temperature
The final temperature would be a weighted average of the initial temperatures, based on the quantities of each liquid. Assuming both cups contain the same amount of water (let's say 1 cup each), the final temperature would be approximately 30 degrees Celsius.
The final temperature of the water after mixing will be the average of the initial temperatures, which is (30 + 50) / 2 = 40 degrees Celsius.
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