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2C4H10(g) + 13O2(g) ---> 8CO2(g) + 10H2O(g)

Now, 96.3 grams(?) of carbon dioxide would be:

m=96.3 n=m/M

M=44.01 = (96.3)/(44.01)

n=? = 2.19

Now, the molar ration of butane:carbon dioxide

1/4n(CO2) =n(C4H10)

= .55 mol


for butane:

m=? m = nM

M=58.24 = 31.86g butane

n=.55

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