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The ideal gas equation.

Pressure * volume = moles * the R constant applicable * temperature in Kelvin

PV = nRT

(1 atmosphere)(202 L) = n(0.08206 L*atm/mol*K)(298.15 K)

= 8.256 moles argon gas

---------------------------------now, a little stoichiometry though you will see that you have the answer here

8.256 moles Ar (6.022 X 1023/1 mole Ar)(1 moles Ar atoms/6.022 X 1023)

= 8.26 moles argon atoms

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