0
What else can I help you with?
BaCl2 plus Al2S3 BaS plus AlCl3?
3BaCl2 + Al2S3 = 3BaS + 2AlCl3 An exercise in balancing coefficients rather than a well known method of making either AlCl3 or BaS.
How many grams of Al2S3 can be formed from the reaction of 108.00 grams of Al with 5.00 grams of S?
The answer i got is 12.33 grams of Al2S3. Below i will try to show the steps i used: n=moles m=mass (grams) M= molecular weight (from periodic table) 2Al + 3S --> Al2S3 nAl= m/M = 9/13 = 0.692307 moles of Al nS= m/M = 8/16 = 0.5 moles of S Limiting Reagent: 1.5 moles of S required for every mole of Al (3:2 ratio) This means that there should be about 1.04 moles of S to completely use up all the Al. Since there is less than this amount of S present (only 0.5 moles), S is the limiting reagent and should be used in the mole calculation of the product Amount of product: 0.5 moles S x (1 mol Al2S3/ 3 mol S) = 0.16666 moles of Al2S3 nAl2S3 = m/M Molecular weight of Al2S3 = (2 x 13) + (3 x 16) = 74 0.16666 moles Al2S3 = m/74 m = 74 x 0.16666 = 12.33 grams of Al2S3 Therefore, 12.33 grams of Al2S3 is formed in this reaction ( hopefully this is right :P )
Determine the Theoritical yield of H2S in moles if 4.0 mol Al2S3 and 4.0 mol H2O are reacted?
The balanced chemical equation for the reaction between Al2S3 and H2O to produce H2S is: Al2S3 + 6 H2O -> 2 Al(OH)3 + 3 H2S From the balanced equation, 1 mol of Al2S3 produces 3 mol of H2S. Therefore, if 4.0 mol of Al2S3 is reacted, the theoretical yield of H2S would be 3 * 4.0 mol = 12.0 mol.
What do you get Aluminium metal reacts with solid sulfur to produce solid aluminium sulfide?
When aluminum metal reacts with solid sulfur, the result is the formation of solid aluminum sulfide. This chemical reaction is a synthesis reaction where aluminum and sulfur combine to form a new compound, aluminum sulfide, with the formula Al2S3.
What represents a correct chemical equation describing the reaction between aluminum metal and sulfur?
The correct chemical equation for the reaction between aluminum metal and sulfur is: 2Al + 3S → Al2S3. This equation shows that two atoms of aluminum combine with three atoms of sulfur to form aluminum sulfide.
What is the chemical equation describing the reaction between aluminum and sulfur?
2Al + 3S ==> Al2S3
BaCl2 plus Al2S3 BaS plus AlCl3?
3BaCl2 + Al2S3 = 3BaS + 2AlCl3 An exercise in balancing coefficients rather than a well known method of making either AlCl3 or BaS.
How many grams of Al2S3 can be formed from the reaction of 108.00 grams of Al with 5.00 grams of S?
The answer i got is 12.33 grams of Al2S3. Below i will try to show the steps i used: n=moles m=mass (grams) M= molecular weight (from periodic table) 2Al + 3S --> Al2S3 nAl= m/M = 9/13 = 0.692307 moles of Al nS= m/M = 8/16 = 0.5 moles of S Limiting Reagent: 1.5 moles of S required for every mole of Al (3:2 ratio) This means that there should be about 1.04 moles of S to completely use up all the Al. Since there is less than this amount of S present (only 0.5 moles), S is the limiting reagent and should be used in the mole calculation of the product Amount of product: 0.5 moles S x (1 mol Al2S3/ 3 mol S) = 0.16666 moles of Al2S3 nAl2S3 = m/M Molecular weight of Al2S3 = (2 x 13) + (3 x 16) = 74 0.16666 moles Al2S3 = m/74 m = 74 x 0.16666 = 12.33 grams of Al2S3 Therefore, 12.33 grams of Al2S3 is formed in this reaction ( hopefully this is right :P )
Represents a correct chemical equation describing the reaction between aluminum metal and sulfur.?
2Al + 3S -> Al2S3
Determine the Theoritical yield of H2S in moles if 4.0 mol Al2S3 and 4.0 mol H2O are reacted?
The balanced chemical equation for the reaction between Al2S3 and H2O to produce H2S is: Al2S3 + 6 H2O -> 2 Al(OH)3 + 3 H2S From the balanced equation, 1 mol of Al2S3 produces 3 mol of H2S. Therefore, if 4.0 mol of Al2S3 is reacted, the theoretical yield of H2S would be 3 * 4.0 mol = 12.0 mol.
What do you get Aluminium metal reacts with solid sulfur to produce solid aluminium sulfide?
When aluminum metal reacts with solid sulfur, the result is the formation of solid aluminum sulfide. This chemical reaction is a synthesis reaction where aluminum and sulfur combine to form a new compound, aluminum sulfide, with the formula Al2S3.
What is the balanced equation of aluminum sulfide water -- aluminum hydroxide dihydrogen sulfide gas?
Al2S3(s) + 6H2O(l) --> 2Al(OH)3(s) + 3H2S(g).
What represents a correct chemical equation describing the reaction between aluminum metal and sulfur?
The correct chemical equation for the reaction between aluminum metal and sulfur is: 2Al + 3S → Al2S3. This equation shows that two atoms of aluminum combine with three atoms of sulfur to form aluminum sulfide.
How do you balance Al plus S equals Al2S3?
2Al+3S--->Al2S3
Chemical formula for aluminum sulfide?
S2Ur5 NO this is wrong! There isn't even an element that is Ur wow! The answer is Al2S3
What is the correct formula for aluminum sulfides?
Al2S3
How many moles of Al2S3 are in 100 g of Al2S3?
100/150.158 is 0.666 moles
