Chromium oxide may refer to:Chromium(II) oxide, CrOChromium(III) oxide, Cr2O3Chromium dioxide (chromium(IV) oxide), CrO2Chromium trioxide (chromium(VI) oxide), CrO3
Nitrogen(IV) oxide is N2O4.
The formula for lead(IV) oxide is PbO2. It is composed of one lead atom bonded to two oxygen atoms.
Balance the oxidation states on the atoms in the molecule. An oxide always contains oxygen in -2 oxidation state , in ionic compounds this is O2-. As the chromium is Cr(IV) in +4 oxidation state, ( shown as an ion Cr4+ ) you can balance the states or charges which ever way to get CrO2 (which you can write as Cr4+ (O2-)2 )
Lead (IV) ion is found in the compound lead(IV) oxide, which has the chemical formula PbO2.
Chromium oxide may refer to:Chromium(II) oxide, CrOChromium(III) oxide, Cr2O3Chromium dioxide (chromium(IV) oxide), CrO2Chromium trioxide (chromium(VI) oxide), CrO3
The formula for sulphur IV oxide is SO2.
SnO2, if you meant (tin(IV) oxide) or tin dioxide that is
The compound formula for titanium(IV) oxide is TiO2.
Nitrogen dioxide NO2 Nitrogen(IV) oxide
The chemical formula for tin(IV) oxide is SnO2. Tin(III) oxide doesn't exist.
The chemical formula for tin(IV) oxide is SnO2. Tin(III) oxide doesn't exist.
Nitrogen(IV) oxide is N2O4.
Lead(IV) oxide would have the formula PbO2
The formula for lead(IV) oxide is PbO2. It is composed of one lead atom bonded to two oxygen atoms.
That would be chromium(IV) selenide with the formula CrSe2
The formula for platinum(IV) oxide is PtO2. Platinum has a 4+ oxidation state in this compound, which is represented by the Roman numeral IV in its name.