Balance the oxidation states on the atoms in the molecule.
An oxide always contains oxygen in -2 oxidation state , in ionic compounds this is O2-.
As the chromium is Cr(IV) in +4 oxidation state, ( shown as an ion Cr4+ ) you can balance the states or charges which ever way to get
CrO2 (which you can write as Cr4+ (O2-)2 )
Chromite is an iron chromium oxide: FeCr 2 O 4
From the formula, you have 2 atoms of Magnesium combine with one oxygen molecule to form 2 molecules of magnesium oxide. So when 4 magnesium atoms combine with two molecules of oxygen you get 4 magnesium oxide molecules. So from 4 moles of magnesium you get 4 moles of Magnesium oxide.
The chemical formula of this is MnO2.It is brown in colour. The oxidation number of Mn is 4 in this compound.
That's old-fashioned nomenclature, but that's okay - the "-ic" suffix means you're dealing with tin with a higher number of valence electrons, in this case, 4. So with tin as +4 and oxygen, as always, as -2, you're going to get a formula of SnO2. Tin with a charge of +2 is the other possible valence option, and that's called "stannous oxide" with the "-ous" suffix, and a formula of SnO. The better way to express stannic oxide is simply to say tin(IV) oxide, and stannous oxide as tin(II) oxide.
The formula for magnesium oxide is MgO, showing that each formula unit of magnesium oxide contains one mole of magnesium ions. Therefore, if there is ample oxygen available, 4 moles of magnesium will form 4 moles of magnesium oxide.
Nitrogen(IV) oxide is N2O4.
Lead(IV) oxide would have the formula PbO2
Chromium has four oxidation states: 2, 3, 4, and 6.Iodine has one, and it's -1.There will be a iodide for each oxidation state of chromium.CrI2 Chromium (II) iodideCrI3 Chromium (III) iodideCrI4 Chromium (IV) iodideCrI6 Chromium (VI) iodide
TiO
6CrO2 (aq) + 10 H+ (aq) --> Cr O72- (aq) + 4 Cr3+ (aq) + 5H2O (l)
Chromium(III) borate has the chemical formula CrBO3.
(Pb2)O
Chromite is an iron chromium oxide: FeCr 2 O 4
Cr(SCN)3 is the chemical formula for the Chromium (III) Thiocyanate. This is because Chromium (III) has a charge of +3 while Thiocyanate has a charge of -1. To balance the charges, we switch the 2 charges. So we have 1 ion of chromium (III) with 3 ions of thiocyanate.
The ionic chemical formula of lead(IV) oxide is: (Pb)4+ + 2 O-.
Burning ammonium dichromate leads to the decomposition of the compound into chromium(III) oxide, nitrogen gas, and water vapor. The reaction produces a green residue of chromium(III) oxide, while the released nitrogen gas produces the characteristic "volcano effect" due to the rapid expansion of the gas.
Plumbic oxide, is Lead (IV) oxide. It has the formula of PbO2, which is neutral. However if you wanted to know the oxidation state of the lead, then it is +4.