The ionic chemical formula of lead(IV) oxide is: (Pb)4+ + 2 O-.
This would be an ionic compound. The lead (IV) ion is a metal, so it would be a cation (positive ion), and the numerals tell us it has a charge of 4+. The oxygen ion is a non-metal, so it would be an anion (negative ion) and it is in group 6A, so it would have a charge of 2-.The ionic compound needs to have a net charge of zero, so we would need two oxygen ions to balance out the charge of each lead (IV) ion.Therefore, the correct formula for lead (IV) oxide is PbO2.
The chemical formula is PbI4.Pb(4+) + 4 I-
The chemical formula of lead tetroxide is Pb3O4.
Lead (IV) chloride is an ionic compound. Lead (IV) cation has a 4+ charge, while chloride ion has a 1- charge, so they combine to form an ionic compound with a formula of PbCl4.
Nitrogen(IV) oxide is N2O4.
Lead(IV) oxide would have the formula PbO2
(Pb2)O
This would be an ionic compound. The lead (IV) ion is a metal, so it would be a cation (positive ion), and the numerals tell us it has a charge of 4+. The oxygen ion is a non-metal, so it would be an anion (negative ion) and it is in group 6A, so it would have a charge of 2-.The ionic compound needs to have a net charge of zero, so we would need two oxygen ions to balance out the charge of each lead (IV) ion.Therefore, the correct formula for lead (IV) oxide is PbO2.
Plumbic oxide, is Lead (IV) oxide. It has the formula of PbO2, which is neutral. However if you wanted to know the oxidation state of the lead, then it is +4.
The chemical formula is PbI4.Pb(4+) + 4 I-
The chemical formula of lead tetroxide is Pb3O4.
The IV in lead IV oxide means that the lead ion has a 4+ charge. The oxide ion has a 2- charge. The charges must cancel out to zero, so there are 2 oxide ions for every 1 lead IV ion, which is what the formula PbO2 shows.
Lead (IV) chloride is an ionic compound. Lead (IV) cation has a 4+ charge, while chloride ion has a 1- charge, so they combine to form an ionic compound with a formula of PbCl4.
Nitrogen(IV) oxide is N2O4.
The formula for the ionic compound formed between S^2- and Pb^4+ is PbS2, where lead (Pb) has a 4+ charge and sulfur (S) has a 2- charge. This results in the compound lead(IV) sulfide.
Tin (IV) oxide is an ionic compound. It consists of tin cations (Sn^4+) and oxide anions (O^2-), which form a lattice structure through ionic bonds.
Lead hydroxide is an ionic compound because it is composed of a metal (lead) and a non-metal (hydroxide ion). In this case, the lead atom donates its electrons to the hydroxide ion to form a stable ionic bond.