Nitrogen(IV) oxide is N2O4.
Nitrogen oxide, with the chemical formula NO, has a total of 12 valence electrons - 5 from nitrogen and 6 from oxygen, with an additional electron due to the negative charge.
The chemical formula of lead tetroxide is Pb3O4.
This term does not refer to any one compound, because Nitrogen has many oxides: Nitrous Oxide = N2O Nitric Oxide = NO Dinitrogen Trioxide = N2O3 Nitrogen Dioxide = NO2 Dinitrogen Tetroxide = N2O4 Dinitrogen Pentoxide = N2O5 Dinitronitramide(IUPAC name) = N(NO2)3 = N4O6
TiO
The ionic chemical formula of lead(IV) oxide is: (Pb)4+ + 2 O-.
Nitrogen oxide, with the chemical formula NO, has a total of 12 valence electrons - 5 from nitrogen and 6 from oxygen, with an additional electron due to the negative charge.
NO = Nitric Oxide (+2) Do not confuse with N2O = Nitrous Oxide ( laughing gas) (+1) NO2 = Nitrogen dioxide (+4) N2O4 = Dinitrogen Tetroxide (+4) Also the NO3^(-) Nitrate anion(+5) NO2^(-) Nitrite anion (+3) N^(3-) the nitride ion as in Na3N (-3) The different names indicate different oxidation states for nitrogen, as indicated!!!!
The chemical formula of lead tetroxide is Pb3O4.
Lead(IV) oxide would have the formula PbO2
This term does not refer to any one compound, because Nitrogen has many oxides: Nitrous Oxide = N2O Nitric Oxide = NO Dinitrogen Trioxide = N2O3 Nitrogen Dioxide = NO2 Dinitrogen Tetroxide = N2O4 Dinitrogen Pentoxide = N2O5 Dinitronitramide(IUPAC name) = N(NO2)3 = N4O6
TiO
The balanced chemical equation for the decomposition of zinc nitrate into zinc oxide, nitrogen dioxide, and oxygen is: 2 Zn(NO3)2 -> 2 ZnO + 4 NO2 + O2
(Pb2)O
The ionic chemical formula of lead(IV) oxide is: (Pb)4+ + 2 O-.
The elemental symbol for nitrogen, N, occurs only once in the formula and it has the subscript 4. This shows that there are four atoms of nitrogen in each molecule of the formula.
The correct formula for Molybdenum IV Chlorate is Mo(ClO3)4.
It is SnO2Why? Because:Tin has a charge of 4 and Oxygen has a charge of 2. Their charges are switched to make a compound; therefore, the chemical formula would be written as Sn2O4. Then, you have to simplify that so it would be written as SnO2.