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Determine the pH of a 5 M HA solution at 25 degrees Ka 7.1 x 10-4?
Wiki User
∙ 16y ago
Given that Ka = 7.1 x 10-4 pKa = -log[Ka]
= 3.15 (2 s.f)
pH = 1/2pka - 1/2log[A-]
= 1/2(3.15) - 1/2log[5]
= 1.575 - (-0.3495)
pH = 1.93 (2 s.f.) So the pH of HA = 1.93
Wiki User
∙ 16y ago
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