It is a strong monoprotic base. Monoprotic means it can accept a proton (and Bronsted-Lowry theory calls proton acceptors BASES) So yes it can accept 1 (mono) proton. Strong acids or bases dissociate completely in aqueous solutions. Therefore this strong monoprotic base would dissociate completely into component ions in solution (this case water) yielding Na+, OH- and H20 (and heat).
A monoprotic base is a molecule that has one functional group that can accept a proton. NaOH for example is a (strong) monoprotic base because it can accept one proton. But amines can also be monoprotic bases.
NaOH Is sodium hydroxide and is a strong base.
NaOH is a base. HCl is an acid. NaCl is a salt. H2O is an oxide.
it is a base, because when NaOH is added to water, it gives off OH- ions.
0.5 M NaOH is a rather concentrated strong base.
A monoprotic base is a molecule that has one functional group that can accept a proton. NaOH for example is a (strong) monoprotic base because it can accept one proton. But amines can also be monoprotic bases.
Neutralization of an acid by a base results in the formation of a salt and water. The general form of the reaction of a monoprotic acid with a base is HA + BOH ==> H2O + BAAn actual example would be hydrochloric acid + sodium hydroxide: HCl + NaOH ==> H2O + NaCl
NaOH Is sodium hydroxide and is a strong base.
NaOH is a base because of its OH- group.
NaOH Is sodium hydroxide and is a strong base.
NaOH is a base. HCl is an acid. NaCl is a salt. H2O is an oxide.
No, it's not correct. Liters*molarity = moles (0.015L)*(1.600moles/L) = 0.024 moles of NaOH One mole of NaOH would neutralize one mole of the MONOprotic acid, so: (0.024 moles of acid)/(0.020L) = 1.2M
it is a base, because when NaOH is added to water, it gives off OH- ions.
0.5 M NaOH is a rather concentrated strong base.
NaOH is formed then. NaOH is a strong base.
NaOH or Sodium Hydroxide is a base
NaOH is a stronga base.NH3 is a weak base.