you need to talk to an arithmetic magician because i have NO IDEA. :D
To determine the normality of HCl (hydrochloric acid), you can perform a titration experiment with a standardized solution of sodium hydroxide (NaOH) of known concentration. By recording the volume of NaOH required to neutralize the HCl, you can calculate the normality of the acid using the formula: Normality = (Molarity of NaOH) x (Volume of NaOH used) / Volume of HCl sample.
The molar mass of NaOH is 40.00 g/mol. Therefore, 40 g of NaOH is equal to 1 mol. Since normality is defined as the number of equivalents of solute per liter of solution, the normality of the 2 L solution containing 40 g of NaOH would be 1 N.
The normality of HCl can be calculated using the equation: Normality (HCl) * Volume (HCl) = Normality (NaOH) * Volume (NaOH). Solving for the normality of HCl gives 6.0N. The molarity of the HCl solution can be calculated using the formula: Molarity = Normality / n-factor. Assuming the n-factor for HCl is 1, the molarity of the HCl solution would be 6.0 M.
Normality of NaOH = molarity of OH- , so for pure NaOH they are equal.When kept in open air the OH- ions come in contact with the slightly (and slowly) soluble carbon dioxide (CO2), which is an ACID forming oxide, thus reacting with the strong base hydroxide:CO2 + H2O -->H2CO3immediately followed by:H2CO3 + OH- --> HCO3-and eventually followed by a second step:HCO3- + OH- --> CO32-While hydroxide is 'disappearing' from solution, it decreases 'its' normality (= concentration of ions, reactive to acids)
If the solution volume remains unchanged, the normality will decrease as the NaOH will react with CO2 present in the air. Of course, if the solution volume is not held constant and if the evaporation rate is sufficient to concentrate the solution - it could also increase (effectively raising the normality of the remaining solution).
To determine the normality of HCl (hydrochloric acid), you can perform a titration experiment with a standardized solution of sodium hydroxide (NaOH) of known concentration. By recording the volume of NaOH required to neutralize the HCl, you can calculate the normality of the acid using the formula: Normality = (Molarity of NaOH) x (Volume of NaOH used) / Volume of HCl sample.
The molar mass of NaOH is 40.00 g/mol. Therefore, 40 g of NaOH is equal to 1 mol. Since normality is defined as the number of equivalents of solute per liter of solution, the normality of the 2 L solution containing 40 g of NaOH would be 1 N.
The normality of HCl can be calculated using the equation: Normality (HCl) * Volume (HCl) = Normality (NaOH) * Volume (NaOH). Solving for the normality of HCl gives 6.0N. The molarity of the HCl solution can be calculated using the formula: Molarity = Normality / n-factor. Assuming the n-factor for HCl is 1, the molarity of the HCl solution would be 6.0 M.
NaOH
Normality of NaOH = molarity of OH- , so for pure NaOH they are equal.When kept in open air the OH- ions come in contact with the slightly (and slowly) soluble carbon dioxide (CO2), which is an ACID forming oxide, thus reacting with the strong base hydroxide:CO2 + H2O -->H2CO3immediately followed by:H2CO3 + OH- --> HCO3-and eventually followed by a second step:HCO3- + OH- --> CO32-While hydroxide is 'disappearing' from solution, it decreases 'its' normality (= concentration of ions, reactive to acids)
If the solution volume remains unchanged, the normality will decrease as the NaOH will react with CO2 present in the air. Of course, if the solution volume is not held constant and if the evaporation rate is sufficient to concentrate the solution - it could also increase (effectively raising the normality of the remaining solution).
To prepare 2N NaOH in 20 ml, first calculate the amount of NaOH needed using the formula: (Molarity x Volume) / Normality. In this case, it would be (2 x 20) / 1 = 40 grams of NaOH. Then, carefully weigh out 40 grams of NaOH and dissolve it in enough water to make a total volume of 20 ml. Make sure to wear appropriate safety gear like gloves and goggles when handling NaOH.
To prepare a 0.1N NaOH solution, dissolve 4g of sodium hydroxide (NaOH) pellets in enough water to make 1 liter of solution. Use a volumetric flask to accurately measure the final volume. Remember to handle NaOH with caution as it is a caustic substance.
The normality of the unknown acid solution is 0.625 N. This can be calculated by using the equation: Normality of acid x volume of acid = Normality of base x volume of base. Given that 25mL of 0.5 N NaOH neutralizes 30mL of the acid, you can set up the equation and solve for the normality of the acid.
ACID VALUE=Normality OF KOK or NaOH*5061/w
To make a 2N NaOH solution, you need to dissolve 80g of NaOH pellets (sodium hydroxide) in enough water to make 1 liter of solution. This will yield a solution with a concentration of 2N (normality), as the equivalent weight of NaOH is 40 g/mol. Be sure to wear appropriate protective gear and handle NaOH with care, as it is a caustic and potentially hazardous chemical.
To calculate normality using specific gravity, you would first determine the concentration of a solution in g/mL. Then, divide the concentration by the equivalent weight of the solute to get the number of equivalents per liter. This value represents normality.