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To prepare 2N NaOH in 20 ml, first calculate the amount of NaOH needed using the formula: (Molarity x Volume) / Normality. In this case, it would be (2 x 20) / 1 = 40 grams of NaOH. Then, carefully weigh out 40 grams of NaOH and dissolve it in enough water to make a total volume of 20 ml. Make sure to wear appropriate safety gear like gloves and goggles when handling NaOH.

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How make 0.5ml of 2N NaOH?

To prepare 0.5 mL of 2N NaOH, you would need to dilute a higher concentration of NaOH solution. Assuming you have a 4N NaOH solution, you would mix 0.25 mL of the 4N solution with 0.25 mL of water to obtain 0.5 mL of 2N NaOH. Be cautious when handling concentrated NaOH solutions, as they are caustic and can cause skin irritation.


How to prepare 2N solution of NaOH in 10 ml of water?

To prepare a 2N solution of NaOH in 10 ml of water, you would need to calculate the amount of NaOH needed based on its molecular weight. Once you have determined the amount needed, dissolve it in 10 ml of water to make the solution. Remember to handle NaOH with caution as it is corrosive.


How can you prepare 0.02 N NaOH solution if i have .2N NaOH?

In order to make 0.02 N NaOH from 0.2 N NaOH, one needs to dilute it by 10 x (10 fold). Depending on the volume of 0.02 N NaOH needed, that will determine the volume of 0.2 N used. For example, to make 100 ml of 0.02 N NaOH, you would dilute 10 mls of 0.2 N to 100 ml. This is seen in the following calculation: (x ml)(0.2 N NaOH) = (100 ml) (0.02 N NaOH) and x = 10 ml


How do you prepare 10 ml of 1M naoh?

To prepare 10 ml of 1M NaOH solution, you would need to dissolve 0.4 grams of NaOH (molar mass of NaOH is 40 g/mol) in enough distilled water to make a total volume of 10 ml. First, measure out 0.4 grams of NaOH using a balance. Then, add this solid NaOH to a small beaker and add distilled water while stirring until the total volume reaches 10 ml. Make sure to handle NaOH with care as it is a caustic substance.


How is a solution of NaOH prepared dissolving 20g of NaOH in 500ml of distiled water solved?

To prepare a 20 g/500 mL solution of NaOH, you would gradually add 20 g of NaOH to 500 mL of distilled water while stirring until fully dissolved. It is important to add the solid to the liquid to prevent splattering. Remember to always use caution and appropriate personal protective equipment when handling NaOH due to its caustic nature.

Related Questions

How make 0.5ml of 2N NaOH?

To prepare 0.5 mL of 2N NaOH, you would need to dilute a higher concentration of NaOH solution. Assuming you have a 4N NaOH solution, you would mix 0.25 mL of the 4N solution with 0.25 mL of water to obtain 0.5 mL of 2N NaOH. Be cautious when handling concentrated NaOH solutions, as they are caustic and can cause skin irritation.


How to prepare 2N solution of NaOH in 10 ml of water?

To prepare a 2N solution of NaOH in 10 ml of water, you would need to calculate the amount of NaOH needed based on its molecular weight. Once you have determined the amount needed, dissolve it in 10 ml of water to make the solution. Remember to handle NaOH with caution as it is corrosive.


How will prepare 200ml of 10 percent NaOH Solution?

Dissolve 0.4 g of NaOH in 100 ml of water. Try it out. Actually it is not suitable to prepare NaOH solutions in standard flasks.It should be made in beakers & must be standardised..This is done to find the correct normality...


How can you prepare 0.02 N NaOH solution if i have .2N NaOH?

In order to make 0.02 N NaOH from 0.2 N NaOH, one needs to dilute it by 10 x (10 fold). Depending on the volume of 0.02 N NaOH needed, that will determine the volume of 0.2 N used. For example, to make 100 ml of 0.02 N NaOH, you would dilute 10 mls of 0.2 N to 100 ml. This is seen in the following calculation: (x ml)(0.2 N NaOH) = (100 ml) (0.02 N NaOH) and x = 10 ml


How do you prepare 10 ml of 1M naoh?

To prepare 10 ml of 1M NaOH solution, you would need to dissolve 0.4 grams of NaOH (molar mass of NaOH is 40 g/mol) in enough distilled water to make a total volume of 10 ml. First, measure out 0.4 grams of NaOH using a balance. Then, add this solid NaOH to a small beaker and add distilled water while stirring until the total volume reaches 10 ml. Make sure to handle NaOH with care as it is a caustic substance.


What amount of NaoH has to be added to 350ml of water to prepare 40normal solution?

560 g in 350 ml (But I am not sure if that large quantity of NaOH will dissolve in 350 ml of wate).


How is a solution of NaOH prepared dissolving 20g of NaOH in 500ml of distiled water solved?

To prepare a 20 g/500 mL solution of NaOH, you would gradually add 20 g of NaOH to 500 mL of distilled water while stirring until fully dissolved. It is important to add the solid to the liquid to prevent splattering. Remember to always use caution and appropriate personal protective equipment when handling NaOH due to its caustic nature.


How do you prepaire 0.05N NaOH from 1N NaOH?

Dissolve 20g of NaOH in about 500 mL of water and dilute with water to 1000mL. Mix well.


How can we Prepare 1mM NaOH?

To prepare 1 mM NaOH solution, you would dissolve 0.040 g of NaOH in enough water to make 1 liter of solution. This concentration is equivalent to 1 millimole of NaOH per liter of solution. Be cautious when handling NaOH as it is a caustic substance.


How many moles of NaOH needed to prepare 300 mL of a 0.2 m solution of NaOH?

To find the moles of NaOH needed, use the formula: moles = concentration (molarity) x volume (liters). First, convert 300 mL to liters (0.3 L). Then, calculate: moles = 0.2 mol/L x 0.3 L = 0.06 moles. Therefore, 0.06 moles of NaOH are needed to prepare 300 mL of a 0.2 M solution.


How many milliliters of 6.0 M NaOH must be used to prepare 1.0 liter of 0.10 M solution?

To prepare a 0.10 M NaOH solution, you need to dilute the 6.0 M solution. You can use the formula: M1V1 = M2V2 where M1 = 6.0 M, V1 is the volume of 6.0 M NaOH needed, M2 = 0.10 M, and V2 = 1000 mL (1.0 L). By substituting the values into the formula, you can calculate the volume of the 6.0 M NaOH needed to prepare the 0.10 M solution.


How would you prepare 385 mL of a 0.766M NaOH solution starting with a 4.03M stock solution?

(385 mL)(0.766 M NaOH) = (X mL)(4.03 M NaOH)4.03X = 294.91X = 73.2 ml============Take 73.2 mL of stock solution and add ( 385 mL - 73.2 mL = 311.8 mL) 312 mL of water to stock solution.