Rb has lower electronegativity (0.8) where as Na is 0.9
Sodium is Na, potassium is K, rubidium is Rb.
Rb > K > Na > Li. The order based on atomic size is Rb > K > Na > Li. Therefore, the size of the circles should reflect this order from largest to smallest.
The electronegativity difference in Na2O is calculated by finding the difference between the electronegativity values of the two elements. Sodium (Na) has an electronegativity of approximately 0.93, and oxygen (O) has an electronegativity of approximately 3.44. Therefore, the electronegativity difference in Na2O is 3.44 - 0.93 = 2.51.
The bond between Na and F is considered polar. Sodium (Na) is a metal, while fluorine (F) is a nonmetal with higher electronegativity. This difference in electronegativity leads to an uneven sharing of electrons in the bond, making it polar.
No, the electronegativity of potassium is lower than the electronegativity of fluorine. Fluorine is the most electronegative element on the periodic table, while potassium is a highly electropositive metal with low electronegativity.
N
Element Rb (Rubidium) has the lowest ionization energy among Rb, Na, C, and F. This is because as you move down a group on the periodic table, the ionization energy typically decreases due to the increase in atomic size. Rubidium is located below sodium (Na) in the same group, so it has a lower ionization energy.
Rb (Rubidium) is the largest element among Li, Na, Rb, and K as you move down the same group or in the same period from left to right on the periodic table.
Rb has the least
Iodine has a lower electronegativity than chlorine. Electronegativity generally decreases as you move down a group on the periodic table, so iodine, being lower in the halogen group than chlorine, has a lower electronegativity.
Sodium is Na, potassium is K, rubidium is Rb.
chlorine
Rb (rubidium) is the largest element among K (potassium), Rb (rubidium), Na (sodium), and Li (lithium). This is because as you move down a group in the periodic table, the atomic size increases due to the addition of more electron shells.
Rb > K > Na > Li. The order based on atomic size is Rb > K > Na > Li. Therefore, the size of the circles should reflect this order from largest to smallest.
Lithium.
The electronegativity difference in Na2O is calculated by finding the difference between the electronegativity values of the two elements. Sodium (Na) has an electronegativity of approximately 0.93, and oxygen (O) has an electronegativity of approximately 3.44. Therefore, the electronegativity difference in Na2O is 3.44 - 0.93 = 2.51.
The bond between Na and F is considered polar. Sodium (Na) is a metal, while fluorine (F) is a nonmetal with higher electronegativity. This difference in electronegativity leads to an uneven sharing of electrons in the bond, making it polar.