Element Rb (Rubidium) has the lowest ionization energy among Rb, Na, C, and F. This is because as you move down a group on the periodic table, the ionization energy typically decreases due to the increase in atomic size. Rubidium is located below sodium (Na) in the same group, so it has a lower ionization energy.
Yes, rubidium (Rb) is more reactive than lithium (Li), potassium (K), sodium (Na), and cesium (Cs). In the alkali metal group, reactivity increases as you move down the periodic table due to the increasing atomic size and the decreasing ionization energy, which makes it easier for the atoms to lose their outermost electron. Thus, Rb, being below K and Na, is more reactive than all of them. However, cesium (Cs) is even more reactive than rubidium.
Atoms of alkaline metals: Rb, Cs, Fr, K, Na, Li. They have a low ionization potential. This potential is expressed in kJ/mol - molar ionization energy and is different for the first, second, third...n electron.
chlorine
These six elements are Li, Na, K, Rb, Cs and Fr.
Element Rb (Rubidium) has the lowest ionization energy among Rb, Na, C, and F. This is because as you move down a group on the periodic table, the ionization energy typically decreases due to the increase in atomic size. Rubidium is located below sodium (Na) in the same group, so it has a lower ionization energy.
Rb has the least
The element with the smallest first ionization energy is Francium, as it is located in Group 1 of the periodic table and has the largest atomic size. Among the elements listed, lithium (Li) would have the smallest first ionization energy as it is closer to the upper right of the periodic table compared to sodium (Na), potassium (K), and rubidium (Rb).
Low
The lowest first ionization energy is found in francium, the element with the highest atomic number. Francium has the lowest ionization energy because the outermost electron is held the weakest due to the large atomic size and shielding effects.
Rb
Lithium (Li) is the most reactive among Li, Na, K, and Rb due to its small atomic size and low ionization energy, making it easier for it to lose its outer electron and form compounds. Sodium (Na) would be next in reactivity, followed by potassium (K) and then rubidium (Rb).
Chlorine typically ionic bonds with metals, so out of the options provided (Ni, Cu, Ga, Rb), it would most likely form an ionic bond with Rb (Rubidium), due to its lower ionization energy.
Atoms of alkaline metals: Rb, Cs, Fr, K, Na, Li. They have a low ionization potential. This potential is expressed in kJ/mol - molar ionization energy and is different for the first, second, third...n electron.
Rb has lower electronegativity than Na. Electronegativity decreases as you move down a group in the periodic table, so Rb, which is located below Na in the periodic table, has lower electronegativity.
Francium has the lowest 1st ionization energy. It badly wants to lose that electron. It is extremely energetically favorable. Basically the elements that are in group 1 and are in the lowest periods.
Rb (Rubidium) is the largest element among Li, Na, Rb, and K as you move down the same group or in the same period from left to right on the periodic table.