Yes, it reacts rapidly tor produce strontium sulfate and hydrogen gas.
2 moles of NaOH will react with 1 mole of H2SO4 based on the balanced chemical equation: 2NaOH + H2SO4 -> Na2SO4 + 2H2O.
When aqueous H2SO4 and aqueous NaOH react by double replacement, they form water (H2O) and sodium sulfate (Na2SO4) as products. The reaction is H2SO4 + 2NaOH → 2H2O + Na2SO4.
The balanced chemical equation is: 3H2SO4 + 2Al → Al2(SO4)3 + 3H2. This shows that 3 moles of H2SO4 react with 2 moles of Al. Therefore, using a mole ratio calculation: (18 mol Al) x (3 mol H2SO4 / 2 mol Al) = 27 moles of H2SO4 will react with 18 moles of Al.
23.56mL 0.5200M H2SO4 100.0mL Sr(OH)2 x (0.1225mol/1000mL) x (1mol Sr(OH)2/1mol H2SO4) = 0.01225mol H2SO4 0.01225mol x (1000mL/.5200mol) = 23.56mL H2SO4 Check it: 2 OH- and 2 H+, so 1-to-1 .5200/.1225 = 4.24 4.24 x 23.56 = 100.01
KBrO3 and KBr do not react with each other because they have same cation K+, but separately they react with H2SO4. 2KBrO3 + H2SO4 -------> K2SO4 + 2HBrO3 2KBr + H2SO4 ----------> K2SO4 + 2HBr
NaOH can react with H2SO4 to form Na2SO4 and water. Ca(OH)2 can react with H2SO4 to form CaSO4 and water. HF can react with H2SO4 to form H2SO4 + HF -> H2O + SO3 + HF + HF, as well as AlCl3O2H2O can react with H2SO4 to form Al2(SO4)3 +H2O. Mg(OH)2 can react with H2SO4 to form MgSO4 and water.
2 moles of NaOH will react with 1 mole of H2SO4 based on the balanced chemical equation: 2NaOH + H2SO4 -> Na2SO4 + 2H2O.
When aqueous H2SO4 and aqueous NaOH react by double replacement, they form water (H2O) and sodium sulfate (Na2SO4) as products. The reaction is H2SO4 + 2NaOH → 2H2O + Na2SO4.
The balanced chemical equation is: 3H2SO4 + 2Al → Al2(SO4)3 + 3H2. This shows that 3 moles of H2SO4 react with 2 moles of Al. Therefore, using a mole ratio calculation: (18 mol Al) x (3 mol H2SO4 / 2 mol Al) = 27 moles of H2SO4 will react with 18 moles of Al.
23.56mL 0.5200M H2SO4 100.0mL Sr(OH)2 x (0.1225mol/1000mL) x (1mol Sr(OH)2/1mol H2SO4) = 0.01225mol H2SO4 0.01225mol x (1000mL/.5200mol) = 23.56mL H2SO4 Check it: 2 OH- and 2 H+, so 1-to-1 .5200/.1225 = 4.24 4.24 x 23.56 = 100.01
KBrO3 and KBr do not react with each other because they have same cation K+, but separately they react with H2SO4. 2KBrO3 + H2SO4 -------> K2SO4 + 2HBrO3 2KBr + H2SO4 ----------> K2SO4 + 2HBr
Mg does not react with cold water while Ca, Sr, and Ba react with cold water to form metal hydroxide and hydrogen gas.
If you want all the H2SO4 to react, you first need a balenced chemical equasion. Mg + H2SO4 --> MgSO4 +H2 Then you calculate using mole ratios moles is expressed as n. n Mg/1 =n H2SO4/1 n Mg= 0.2mol It's the same because there are no coefficients in front of the reactants.
The reaction between MgF2 and H2SO4 will produce MgSO4 and HF as products. MgF2 will react with H2SO4 to form MgSO4 and HF through a double displacement reaction.
NaCl and H2SO4 doesn't react.
You would need to react iron with sulfuric acid (H2SO4) to produce iron sulfate (FeSO4).
We need to go from grams of CuO to mL of H2SO4. Atomic weight of CuO = 63.55 g Cu + 16 g O = 79.55 g CuO (.80 g CuO) * (1 mol CuO / 79.55 g CuO) = .0100566 mol CuO (g CuO cancel) Since the moles of CuO is a 1:1 ratio to H2SO4 (see balanced equation) we know that: mol CuO = mol H2SO4 or 0.0100566 mol CuO = 0.0100566 mol H2SO4 3.0 M of H2SO4 means that there is 3 mol / 1 L. So we can divide this by the moles to get L then mL of H2SO4 (0.0100566 mol H2SO4) * (1 L H2SO4 / 3 mol H2SO4) * (1000 mL H2SO4 / 1 L H2SO4) = 3.4 mL H2SO4 (mol H2SO4 and L H2SO4 cancel) So 3.4 ml of H2SO4 is needed to react with 0.80 g of CuO.