It depends. If Fluorine is bonded to Hydrogen then it would be greater, having present Hydrogen Bonding-the strongest Intermolecular Force. Iodine,I2, has many more electrons than fluorine, F2,so London dispersion forces are much stronger explaining why fluorine is a gas and iodine is a solid under standard conditions.
The strength of the intermolecular forces will determine what phase the substance is in at any given temperature and pressure. Consider the halogens for example, fluorine and chlorine are gases, while bromine is a liquid and iodine is a solid at room temperature. When considering the intermolecular forces present, each of these substances only has London forces, which increase in magnitude with increasing size of the molecules, and size increases as you go down a group in the periodic table. So, fluorine has the smallest intermolecular forces, and iodine has the largest. This explains why these different substances exist in different phases when at room temperature and pressure. The molecules in fluorine, for example, are only slightly attracted to each other, and therefore the substance exists as a gas. The stronger intermolecular forces in bromine, however, hold the molecules close to each other, but not quite strongly enough to prevent the molecules from sliding past each other; this makes bromine a liquid. Finally, in iodine, the intermolecular forces are actually strong enough that the molecules are held in fixed positions relative to each other, thus making iodine a solid.
Iodine is bound together by van der Waals forces.
Well, a crystal is solid. If you mean, are ionic bonds stronger than covalent bonds, then the answer would be almost always. With a few exceptions, the ionic bond has a greater intermolecular force than a covalent bond. One exception might be a diamond and a weak ionic compound like RbBr.
For a start not all the other halogens are gases only chlorine and fluorine, bromine is a liquid and astatine is also a solid. The increase in boiling/melting point as you go down the group is due to the fact the intermolecular forces get stronger. Halogens are non polar, so the only forces between the molecules are van der waals' forces, these forces come from random movement of electrons, When electrons sway in one direction they make that side slightly more negative than the other forming a temporary dipole, this in turn induces a dipole on the molecule next to it, the slightly negative side is then attracted to the slightly positive side. The more electrons the more random movement of electrons and hence stronger van der waals' forces. Iodine has 106 electrons (its a diatomic molecule), this is alot more than chlorine and fluorine hence why iodine is a solid and the others aren't (excluding astatine).
On the periodic table, the symbol for iodine is I and the symbol for fluorine is F.
Iodine has stronger intermolecular forces.
The strength of the intermolecular forces will determine what phase the substance is in at any given temperature and pressure. Consider the halogens for example, fluorine and chlorine are gases, while bromine is a liquid and iodine is a solid at room temperature. When considering the intermolecular forces present, each of these substances only has London forces, which increase in magnitude with increasing size of the molecules, and size increases as you go down a group in the periodic table. So, fluorine has the smallest intermolecular forces, and iodine has the largest. This explains why these different substances exist in different phases when at room temperature and pressure. The molecules in fluorine, for example, are only slightly attracted to each other, and therefore the substance exists as a gas. The stronger intermolecular forces in bromine, however, hold the molecules close to each other, but not quite strongly enough to prevent the molecules from sliding past each other; this makes bromine a liquid. Finally, in iodine, the intermolecular forces are actually strong enough that the molecules are held in fixed positions relative to each other, thus making iodine a solid.
Iodine is bound together by van der Waals forces.
Well, a crystal is solid. If you mean, are ionic bonds stronger than covalent bonds, then the answer would be almost always. With a few exceptions, the ionic bond has a greater intermolecular force than a covalent bond. One exception might be a diamond and a weak ionic compound like RbBr.
For a start not all the other halogens are gases only chlorine and fluorine, bromine is a liquid and astatine is also a solid. The increase in boiling/melting point as you go down the group is due to the fact the intermolecular forces get stronger. Halogens are non polar, so the only forces between the molecules are van der waals' forces, these forces come from random movement of electrons, When electrons sway in one direction they make that side slightly more negative than the other forming a temporary dipole, this in turn induces a dipole on the molecule next to it, the slightly negative side is then attracted to the slightly positive side. The more electrons the more random movement of electrons and hence stronger van der waals' forces. Iodine has 106 electrons (its a diatomic molecule), this is alot more than chlorine and fluorine hence why iodine is a solid and the others aren't (excluding astatine).
london dispersion forces:) both iodine and hexane are non-polar meaning that the dominant IMF in each of them is the LDF. therefore the non-polar solute-non-polar solvent interaction would be LDF.
Yes. Fluorine is more reactive than iodine.
On the periodic table, the symbol for iodine is I and the symbol for fluorine is F.
yes it is - gentle warming will change it to vapor though.
Regardless of the state, the forces which hold an iodine moolecule together are the same for any other covalent bond: the electric force between the two opposite charges (the positive nuclei and the negative electrons).
Do your homework yourself C: I had the exact same sheet last week hardy har.
An iodine molecule is held together by covalent bonds