Yes, lead(II) nitrate can conduct electricity when dissolved in water as it dissociates into lead(II) ions and nitrate ions which are free to carry an electric current. However, solid lead(II) nitrate does not conduct electricity as the ions are not free to move.
The molecular formula of lead(II) nitrate is Pb(NO3)2, and the molecular formula of sodium nitrate is NaNO3. Lead(II) nitrate contains one lead atom, two nitrate ions (NO3-), while sodium nitrate contains one sodium atom and one nitrate ion.
When lead(II) nitrate and sodium sulfate react, lead(II) sulfate and sodium nitrate are formed through a double displacement reaction. The balanced chemical equation for this reaction is: Pb(NO3)2 + Na2SO4 → PbSO4 + 2NaNO3. Lead(II) sulfate is a precipitate that appears as a white solid when this reaction occurs.
Lead(II) nitrate and sodium iodide will yield lead(II) iodide and sodium nitrate. This is a double displacement reaction, where the cations and anions switch partners resulting in the formation of two new compounds.
NO. Platinum will not react with lead(II) nitrate because platinum is BELOW lead in the activity series.
The chemical symbol for lead II nitrate is Pb(NO3)2.
Lead (II) Nitrate
Its Colorless
The formula for lead (II) nitrate is Pb(NO3)2.
The molecular formula of lead(II) nitrate is Pb(NO3)2, and the molecular formula of sodium nitrate is NaNO3. Lead(II) nitrate contains one lead atom, two nitrate ions (NO3-), while sodium nitrate contains one sodium atom and one nitrate ion.
probably it is Lead(II)nitrate
When reactants lead(II) nitrate and sodium iodide are combined, a double displacement reaction occurs. Lead(II) iodide (insoluble in water) and sodium nitrate are formed, leading to a white precipitate of lead(II) iodide and a solution of sodium nitrate.
Lead compounds tend to be blue in flame tests
When lead(II) nitrate and sodium sulfate react, lead(II) sulfate and sodium nitrate are formed through a double displacement reaction. The balanced chemical equation for this reaction is: Pb(NO3)2 + Na2SO4 → PbSO4 + 2NaNO3. Lead(II) sulfate is a precipitate that appears as a white solid when this reaction occurs.
Lead(II) nitrate and sodium iodide will yield lead(II) iodide and sodium nitrate. This is a double displacement reaction, where the cations and anions switch partners resulting in the formation of two new compounds.
NO. Platinum will not react with lead(II) nitrate because platinum is BELOW lead in the activity series.
The chemical symbol for lead II nitrate is Pb(NO3)2.
This is a double displacement reaction. 2KI + Pb(NO3)2 --> 2KNO3 + PbI2 Potassium iodide + Lead(II) nitrate --> Potassium nitrate + Lead(II) iodide A bright yellow precipitate will form when these two react.