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C-C-C-C-C

Ok so off the fourth carbon there is a double bonded O as well as a single bonded H. then there are only 10 H's therefor taking the formula from C_5H_12O to C_5H_10O. oxidation..

Ps. Hydrogens are single bonded to each carbon, the end carbons will have three and the middle ones will have two( excluding the fourth one)

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