To calculate the oxidation state of fluorine in O2F2, first draw a diagram of the molecule: F-O-O-F
Determine the most electronegative atom(s), which are fluorines -- the most electronegative atom there is. Being in the group 7A, a fluoride ion would gain an electron to a -1 charge, so each has an oxidation number of -1.
The oxygens, therefore, have an oxidation number of +1 each.
The oxidation number of Fluorine is -1.
In F2 it has oxidation number of zero. In compounds it has an ON of -1 always!
Fluorine has the -1 oxidation state in its compounds.
In itse elemental form its oxidation state is 0 as it is for all pure elements.
0 oxidation state
The compounds of oxygen with fluorine are:OF2, O2F2, O3F2
F2 does not combine directly with O2. so there will be no reaction under ordinary condition. But F2 does forms two oxides OF2 & O2F2. OF2 is prepared by passing F2 into 2% NaOH solution and O2F2 is formed when an electric discharge is passed through a mixture of O2 & F2 at very low pressure and temperature
F-O-O-F Each oxygen has 2 lone pairs on it, while each fluorine has 3 lone pairs. Because of the 3 lone pairs on each oxygen, the bonding angles present are 109.5°.
We can draw it as H-O-O-H . However it is NOT linear molecule. The two H-O bonds are angled to the O-O bonds by about 94.8 o. Then the lone pairs of electrons on the oxygens repulse each other, so this twists the H-O bonds into two different planes , with and angler of 115 o between each plabne. So it is actually a 3-dimensional molecule. Have a look in Wikipedia under Hydrogen peroxide.
The compounds of oxygen with fluorine are:OF2, O2F2, O3F2
Compounds of fluorine and oxygen are: OF2, O2F2, O3F2.
Dioxygen Difluoride
Oxygen is the element whose most common oxidation state is -2. In fact, it only shows oxidation states of +2,+1 in compounds OF2, O2F2. It is because oxygen is the second most electronegative element behind Fluorine.
Oxygen and fluorine can form two different molecules. One is oxygen difluoride (OF2), and the other is dioxygen difluoride (O2F2).
Dioxygen difluoride
_ _F-O=O/ F-+
Dioxygen difuoride
F2 does not combine directly with O2. so there will be no reaction under ordinary condition. But F2 does forms two oxides OF2 & O2F2. OF2 is prepared by passing F2 into 2% NaOH solution and O2F2 is formed when an electric discharge is passed through a mixture of O2 & F2 at very low pressure and temperature
F-O-O-F Each oxygen has 2 lone pairs on it, while each fluorine has 3 lone pairs. Because of the 3 lone pairs on each oxygen, the bonding angles present are 109.5°.
Formula: O2F2
Dioxygen difluoride (fluorine peroxide) is a compound of fluorine and oxygen with the molecular formula O2F2. It can exist as an orange-colored solid which melts into a red liquid at −163 °C (110 K). It is an extremely strong oxidant and decomposes into oxygen and fluorine even at −160 °C (113 K) at a rate of 4% per day: its lifetime at room temperature is thus extremely short.[1] Dioxygen difluoride reacts vigorously with nearly every chemical it encounters – even ordinary ice – leading to its onomatopoeic nickname "FOOF" (a play on its chemical structure and its explosive tendencies).