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To calculate the oxidation state of fluorine in O2F2, first draw a diagram of the molecule: F-O-O-F

Determine the most electronegative atom(s), which are fluorines -- the most electronegative atom there is. Being in the group 7A, a fluoride ion would gain an electron to a -1 charge, so each has an oxidation number of -1.

The oxygens, therefore, have an oxidation number of +1 each.

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