O2- would have the electron configuration of 1s2 2s2 2p6 Because the Oxygen has a charge of 2-, that means it has two more electrons than normal. So you do the electron configuration normally, then add two electrons! =]
The electron configuration for oxygen is [He]2s2.2p4.The electron configuration for sulfur is [Ne]3s2.3p4.
The electronic configuration of einsteinium is: [Rn]5f11.7s2.
The electron configuration for V3 is Ar 3d2.
The electron configuration of V3 is Ar 3d2.
The electron configuration of curium is [Rn]5f7.6d1.7s2.
Li, Be, O: the first term in the abridged electron configuration is [He]. Ca, K: the first term in the abridged electron configuration is [Ar].
Electron configuration for oxygen (O) is 1s2 2s2 2p4. The valency is 2-.
The noble gas configuration of oxygen (O) is [He] 2s^2 2p^4, where [He] represents the electron configuration of the nearest noble gas, helium.
Oxide ion (O²⁻) has the electron configuration of a noble gas neon (Ne), which is 1s² 2s² 2p⁶.
Yes it is possible to write the noble gas configuration of all elements, though it is not possible to list all of them here.
The electron configuration for oxygen is [He]2s2.2p4.The electron configuration for sulfur is [Ne]3s2.3p4.
A cation has a depleted electron configuration.
The electron configuration for beryllium, Be, is 1s22s2.
The electronic configuration of einsteinium is: [Rn]5f11.7s2.
The electron configuration of francium is [Rn]7s1.
Hydrogen electron configuration will be 1s1.
Uranium electron configuration: [Rn]5f36d17s2