None of them, KCl is ionic, HF, H2O and F2 are covalent
Single replacement. The F2 replaces Cl to form HF and Cl2.
H2o
From what I've been told, because HF is a weak acid and therefore a weak electrolyte you are not supposed to break it up into cations and anions. Not sure how you would be getting F- as a spectator in other aq reactions, unless there's an extra rule that I simply haven't been taught.
XeF4+H2O->XeO3+HF+H2O
None of them, KCl is ionic, HF, H2O and F2 are covalent
U3O8 + HNO3 yields UNO3 + H2 yields UO2 + HF yields UF4 + F2 yields UF6
Single replacement. The F2 replaces Cl to form HF and Cl2.
H2o
From what I've been told, because HF is a weak acid and therefore a weak electrolyte you are not supposed to break it up into cations and anions. Not sure how you would be getting F- as a spectator in other aq reactions, unless there's an extra rule that I simply haven't been taught.
XeF4+H2O->XeO3+HF+H2O
hf + koh -> h2o + kf
Fluorine is hardly soluble but it might react with water in two different ways.Possibly:2 F2 + 2 H2O -- > 4 HF + O2(g) or2 F2 + H2O + OH- --> F2O + HF2- + H2O
Fluorine reacts with water to produce Hydrogen Fluoride(HF) and Oxygen(O2).2 H2O + 2 F2 ----> 4 HF + O2
The chemical equation is:SF4 + 2 H2O = SO2 + 4 HF
2 HCl + F2 --> 2 HF + Cl2 HCl is hydrochloric acid, and when it reacts with F2 (Flourine-a non-metal), it yields hydroflouric acid and Chlorine
tHe chemical equation is:SF4 + 2 H2O = SO2 + 4 HF