XeF4+H2O->XeO3+HF+H2O
The formula for xenon tetrafluoride is XeF4.
There are two lone pairs on XeF4.
The chemical equation for Na2S (sodium sulfide) reacting with H2O (water) is: Na2S + H2O → 2NaOH + H2S
The net ionic equation for the given reaction is H+ (aq) + OH- (aq) → H2O (l)
When NaHCO3 is combined with CaCl2 and H2O, a reaction will occur. However, the specific products depend on the conditions of the reaction - typically, NaHCO3 will react with CaCl2 to form NaCl, CaCO3, and H2O.
The correct answer is:BH3 sp2BeCl2 spPCl5 sp3dNH3 sp3SF6 sp3d 2Type your answer here...
XeF4 is square planar
It will give a salt and water, so if it is HCl and NaOH it will give you NaCl and H2O
lCl3 = T- shaped XeF4 =Square planar SF4 =Seesaw H20 =Bent XeF2 =Linear
The formula for xenon tetrafluoride is XeF4.
CuO + 2HCL - CuCl2 + H2O
There are two lone pairs on XeF4.
The chemical equation for Na2S (sodium sulfide) reacting with H2O (water) is: Na2S + H2O → 2NaOH + H2S
Potassium carbonate plus nitric acid. K2CO3 + 2HNO3 = 2KNO3 + H2O + CO2 .
cl2o7+h2o
No it is not a tetrahedral!
These are some possible ionic equation for CuSO4 plus H2O: Cu2+ + 6 H2O --> Cu(H2O)6 Cu(H2O)62+ + H2O <--> Cu(OH)(H2O)5+ + H3O+ This makes a solution of copper sulfate weakly acidic.