BBr3
The chemical formula for boron tribromide is BBr3.
The chemical formula for boron tribromide is BBr3.
The chemical symbol for boron tribromide is BBr3. It is a colorless liquid with a pungent odor and is used in organic synthesis reactions.
The covalent compound BBr3 is named boron tribromide.
The compound that would form between boron and bromine is boron tribromide, which has the formula BBr3. It is a colorless, fuming liquid with a pungent odor and is commonly used in organic synthesis as a Lewis acid catalyst.
The chemical formula for boron tribromide is BBr3.
The chemical formula for boron tribromide is BBr3.
BBr3 itself is the molecular formula of Boron Tribromide.
The chemical symbol for boron tribromide is BBr3. It is a colorless liquid with a pungent odor and is used in organic synthesis reactions.
The covalent compound BBr3 is named boron tribromide.
The compound that would form between boron and bromine is boron tribromide, which has the formula BBr3. It is a colorless, fuming liquid with a pungent odor and is commonly used in organic synthesis as a Lewis acid catalyst.
The molecular geometry of boron tribromide is trigonal planar. This is because boron has sp2 hybridization, and the molecule has three surrounding bromine atoms arranged in a planar triangle around the boron atom.
BBr3 is boron tribromide. It is a chemical compound composed of one boron atom and three bromine atoms.
The formula for pentasulfur tribromide is S5Br3.
B2Br3 is the chemical formula for diboron tribromide. It is a boron compound composed of two boron atoms and three bromine atoms. It is a colorless liquid that reacts vigorously with water.
The atomic mass of boron is 10.811 while that of bromine is 79.904. Thus the ratio of the mass of bromine to the total mass of boron tribromide must be: 3(79.904)/[3(79.904) + 10.811] = 0.9568. The required mass of BBr3 thus is 11.8/0.9568 = 12.3 g, to the justified number of significant digits.
The resonance of boron tribromide (BBr3) involves the delocalization of electrons around the boron atom due to the presence of the three bromine atoms. This results in the stabilization of the molecule and a more even distribution of charge.