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What is the molecular geometry of boron tribromide?

The molecular geometry of boron tribromide (BBr3) is trigonal planar. The boron atom is surrounded by three bromine atoms, creating a trigonal planar shape with bond angles of 120 degrees.


What is the molecular formula for BBr3?

BBr3 itself is the molecular formula of Boron Tribromide.


What is the significance of BF3 hybridization in molecular geometry and chemical bonding?

The significance of BF3 hybridization in molecular geometry and chemical bonding lies in its ability to explain the shape of the molecule and how it forms bonds. Hybridization helps us understand how the atomic orbitals of boron combine to form new hybrid orbitals, which in turn determine the geometry of the molecule and its bonding behavior. In the case of BF3, the sp2 hybridization of boron leads to a trigonal planar geometry and the formation of three strong covalent bonds with fluorine atoms. This understanding of hybridization is crucial in predicting the properties and reactivity of BF3 and similar molecules.


What is the formula for boron tribromide?

The chemical formula for boron tribromide is BBr3.


What is the chemical formula for boron tribromide?

The chemical formula for boron tribromide is BBr3.


What is Name of the covalent compound BBr3?

The covalent compound BBr3 is named boron tribromide.


What compound is BBr3?

BBr3 is boron tribromide. It is a chemical compound composed of one boron atom and three bromine atoms.


Formula for boron tribromide?

The chemical formula for boron tribromide is BBr3. It is a colorless, fuming liquid that is used in organic synthesis as a reagent.


What is the hybridization of the boron atom in BF3?

The boron atom in BF3 has sp2 hybridization.


Chemical symbol for boron tribromide?

The chemical symbol for boron tribromide is BBr3. It is a colorless liquid with a pungent odor and is used in organic synthesis reactions.


What is Boron Trifluoride molecular shape?

Boron Trifluoride has a trigonal planar molecular shape, with an sp2 hybridization. This means the molecule is flat and the three fluorine atoms are arranged symmetrically around the boron atom in a triangular shape.


How many grams of boron tribromide must be weighed out to get a sample of boron tribromide that contains 11.8 g of bromine?

The atomic mass of boron is 10.811 while that of bromine is 79.904. Thus the ratio of the mass of bromine to the total mass of boron tribromide must be: 3(79.904)/[3(79.904) + 10.811] = 0.9568. The required mass of BBr3 thus is 11.8/0.9568 = 12.3 g, to the justified number of significant digits.