Well my text book states that there is only 8 isotopes in Mercury but if you are looking for the stables isotopes in Mercury they are only 7 stable isotopes which are 196,198,199,200,201,202,and 204.
A complete answer would require specification of a temperature, but at 20C, mercury is reported to have a density of 13.5939 grams per milliliter, so that 1.80 mL would have a mass of 1.80 X 13.5939 or 245 grams, to the justified number of significant digits. The gram atomic mass, which is the mass of Avogadro's number of mercury atoms, is 200.6; and Avogadro's Number is about 6.022 X 1023. Therefore the number of atoms in the volume specified is (245/200.6)(6.022) X 1023 or 7.345 X 1021 atoms.
3,45 grams of H2O contain 1,154.10e23 oxygen atoms.
The density of mercury is about 13.6 grams per cubic centimeter. So, 120 grams of mercury would occupy approximately 8.82 cubic centimeters of volume.
Mercury is an element (Hg) so only mercury atoms appear. That being said, natural mercury is likely comprised of several different flavors of the mercury atom, called isotopes, which accounts for why mercury's mass on the periodic table is not a whole number.
Density = mass/volume ( Mercury is 13.534 grams/milliliter, and milliliter = cubic centimeter ) 13.534 g/ml = grams/9.1 cc (or ml) = 123.1594 grams of Hg ( Mercury) 123.1594 grams Hg (1 mole Hg/200.6 grams)(6.022 X 10^23/1 mole Hg) = 3.7 X 10^23 atoms of mercury
2,88 grams of helium have 3,761.1023 atoms; 16,4 grams of zinc have 1,511.1023 atoms.
Well my text book states that there is only 8 isotopes in Mercury but if you are looking for the stables isotopes in Mercury they are only 7 stable isotopes which are 196,198,199,200,201,202,and 204.
A complete answer would require specification of a temperature, but at 20C, mercury is reported to have a density of 13.5939 grams per milliliter, so that 1.80 mL would have a mass of 1.80 X 13.5939 or 245 grams, to the justified number of significant digits. The gram atomic mass, which is the mass of Avogadro's number of mercury atoms, is 200.6; and Avogadro's Number is about 6.022 X 1023. Therefore the number of atoms in the volume specified is (245/200.6)(6.022) X 1023 or 7.345 X 1021 atoms.
To convert grams to moles you need mercury's atomic mass: 200.59 grams/mole. You can then take your measurement and divide it by the atomic mass to get moles.Grams ÷ Atomic mass = Moles50.15 grams ÷ 200.59 grams = 0.2500 moles Hg
Two mercury atoms present in mercury(II)chloride.
The number of mercury atoms is 11,74458.10e23.
The mass of mercury is approximately 200.59 grams per mole.
grams of mercury (Hg) 1 mole x 1 mole Avogadro's number (6.022 x 1023) of atoms 200.6 grams Hg 1 mole 200.6 grams Hg = x = ≈ 3.3311192-23 atoms Hg 1 mole 6.022 x 1023 atoms 6.022 x 1023 atoms
603 grams of mercury are equivalent to 3,006 moles.
370 grams of mercury is equal to 1,844 moles.
Mercury(l) chloride