When NaOH reacts with CO2, it forms sodium carbonate and water. This reaction increases the pH of the solution because sodium carbonate is a basic compound. The presence of more basic compounds in the solution raises the pH level.
When carbon dioxide (CO2) reacts with sodium hydroxide (NaOH), it forms sodium carbonate (Na2CO3) and water (H2O). This reaction increases the pH level of the solution because sodium carbonate is a basic compound.
Heating NaOH before adding BaCl2 helps to dissolve NaOH completely in water, ensuring that no solid NaOH remains undissolved in the solution. This is important because the reaction between BaCl2 and NaOH requires the NaOH to be in solution to react with the BaCl2. Heating the solution can also speed up the reaction between NaOH and BaCl2.
The general reaction type between FeCl3 and NaOH is a double displacement reaction. This reaction results in the formation of Fe(OH)3, a precipitate, and NaCl, which remains in solution.
Phenolphthalein reacts with NaOH in a neutralization reaction, where the acidic H+ ions in phenolphthalein are replaced by the basic OH- ions from NaOH. This reaction leads to the formation of a pink color indicating the basic nature of the solution.
This is an exothermic reaction, which releases heat energy as the lye (NaOH) dissolves in water. This heat is generated due to the interaction between the ions in the NaOH and the water molecules.
When carbon dioxide (CO2) reacts with sodium hydroxide (NaOH), it forms sodium carbonate (Na2CO3) and water (H2O). This reaction increases the pH level of the solution because sodium carbonate is a basic compound.
Heating NaOH before adding BaCl2 helps to dissolve NaOH completely in water, ensuring that no solid NaOH remains undissolved in the solution. This is important because the reaction between BaCl2 and NaOH requires the NaOH to be in solution to react with the BaCl2. Heating the solution can also speed up the reaction between NaOH and BaCl2.
The general reaction type between FeCl3 and NaOH is a double displacement reaction. This reaction results in the formation of Fe(OH)3, a precipitate, and NaCl, which remains in solution.
Phenolphthalein reacts with NaOH in a neutralization reaction, where the acidic H+ ions in phenolphthalein are replaced by the basic OH- ions from NaOH. This reaction leads to the formation of a pink color indicating the basic nature of the solution.
This is an exothermic reaction, which releases heat energy as the lye (NaOH) dissolves in water. This heat is generated due to the interaction between the ions in the NaOH and the water molecules.
The reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) is 1:1, so the moles of NaOH used in the reaction can be used to determine the moles of HCl in the solution. Using the volume and concentration of NaOH, you can calculate the moles of NaOH used. Then, using the balanced equation, you can determine the moles of HCl, which can be used to find the molarity of HCl in the solution.
The reaction between HNO3 and NaOH is a 1:1 molar ratio. This means that the moles of HNO3 required to neutralize the NaOH is the same as the moles of NaOH. Given that 20.0 ml of HNO3 is needed to neutralize 10.0 ml of a 1.67 M NaOH solution, the molarity of the HNO3 solution is twice the molarity of the NaOH solution, which is 3.34 M.
No. It is a physical process, so it technically isn't a reaction.
The reaction equation between NaOH and potassium hydrogen tartrate (KHT) is: 2KHT + 2NaOH → 2KNaTartrate + 2H2O
Fe3+ + 3OH- _____> Fe(OH)3
To prepare a 10 N solution of NaOH, you would dissolve 400 g of NaOH pellets in enough distilled water to make 1 liter of solution. Remember to add the NaOH to the water slowly and carefully due to the exothermic nature of the reaction. Finally, stir the solution until all of the NaOH has fully dissolved.
H3PO4 + NaOH ----> Na2HPO4 + H2O