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how many grams iron will absorb 900 joules of heat and only change temperature by .2 degrees?
Allison Rees
200 grams
nshokamombo
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If it takes 31500 joules of heat to warm 750 g of water what was the temperature change?
10 degrees Celsius
How do you increase the the temperature of 500 grams of water from 20 degrees Celsius to 100 degrees Celsius?
q(joules) = mass * specific heat * change in temperature q = (500 grams H2O)(4.180 J/goC)(100o C - 20o C) = 1.7 X 105 joules ================add this much heat energy to the water
A particular sample of iron requires 562 Joules to raise its temperature from 25 degreee Celsius to 50 degrees Celsius. What must be the mass of the sample of iron?
The change in temperature is 25 degrees Celsius, meaning it takes 22.48 joules per degree of change. The specific heat of iron is 0.449 J/g degree Celsius. This means that the mass of iron must be 50.07 grams
How many calories are required to increase the temperature of a 27.3 g sample of copper from 36.2 degrees Celsius to 74.4 degrees Celsius?
I will work in Joules, then convert to calories.q(Joules) = mass * specific heat * change in temperature Cq = (27.3 g Cu)(0.385 J/gC)(74.4o C - 36.2o C)= 402 Joules (1 calorie/4.184 Joules)= 96.1 calories===========
If 705g of water is heated 889J how much will its temperature increase?
It take 4.2 Joules to raise 1 gram of water by 1 degree Celsius. Each gram of water is heated by 1.26 Joules, creating an increase in temperature of .3 degrees Celsius.
What is an amount of water whose temperature would change by 15 degrees Celsius when it absorbs 2646 joules of heat energy?
The amount of water whose temperature would change by 15 degrees Celsius when it absorbs 2646 joules of heat energy is 42,2g H2O.
How many joules are needed to change the temperature of 100 g of water from 20 degrees Celsius to 40 degrees celsius?
8.200 J
How many joules does it take to raise temperature from 30 degrees Celsius to 45 degrees Celsius?
15.37684 joules
If it takes 31500 joules of heat to warm 750 g of water what was the temperature change?
10 degrees Celsius
How many joules are absorbed by the water with a mass of 8 kg in order to raise the temperature from 20 degrees to 70 degrees?
q(joules) = mass * specific heat * change in temperature ( 8 kg = 8000 grams ) q = (8000 grams H2O)(4.180 J/gC)(70o C - 20o C) = 1.7 X 106 joules ============
What is the quantity of heat in joules needed to raise the temperature of 40.0g of Al from 25 degrees Celsius to 50 degrees Celsius?
E = mass x specific heat x Δ°T Δ°T = new temperature - original temperature where Δ°T is equal to temperature change (Celsius in this case). The specific heat of Al is 0.900 J/g°C. Before we proceed to find the quantity of heat in joules, we must first find the temperature change. To calculate the temperature change, we must subtract the original temperature from the new temperature. Δ°T = 50°C - 25°C = 25°C In order to find the quantity of heat (joules), we must multiply mass, specific heat, and the temperature change (calculated above). E = 40.0g x 0.900 J/g°C x 25°C = 900 Joules or 9.0 x 102 Joules
How do you increase the the temperature of 500 grams of water from 20 degrees Celsius to 100 degrees Celsius?
q(joules) = mass * specific heat * change in temperature q = (500 grams H2O)(4.180 J/goC)(100o C - 20o C) = 1.7 X 105 joules ================add this much heat energy to the water
Is heat is measured in degrees Celsius?
Temperature is measured in celcius.Heat is measured in joules.
A particular sample of iron requires 562 Joules to raise its temperature from 25 degreee Celsius to 50 degrees Celsius. What must be the mass of the sample of iron?
The change in temperature is 25 degrees Celsius, meaning it takes 22.48 joules per degree of change. The specific heat of iron is 0.449 J/g degree Celsius. This means that the mass of iron must be 50.07 grams
How many calories are required to increase the temperature of a 27.3 g sample of copper from 36.2 degrees Celsius to 74.4 degrees Celsius?
I will work in Joules, then convert to calories.q(Joules) = mass * specific heat * change in temperature Cq = (27.3 g Cu)(0.385 J/gC)(74.4o C - 36.2o C)= 402 Joules (1 calorie/4.184 Joules)= 96.1 calories===========
How many joules of energy are required to raise the temperature of 74g of water from 20 degrees to 70 degrees celsius?
15480.80
How much heat in joules to heat a 40 g sample of aluminum from 73 degrees f to 142 degrees f?
q( in Joules ) = mass * specific heat * change in temperature [ convert temps--Tf = Tc(1.80) + 32 ] q = (40 g)(0.90 J/gC)(61.1o C - 22.8o C) = 1.4 X 103 Joules =============
