200 grams
The specific heat capacity of water is 4.184 J/g°C. The change in temperature is 35.5°C - 21°C = 14.5°C. Using the formula Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature, you can calculate that the heat required is approximately 1554.7 joules.
I will work in Joules, then convert to calories.q(Joules) = mass * specific heat * change in temperature Cq = (27.3 g Cu)(0.385 J/gC)(74.4o C - 36.2o C)= 402 Joules (1 calorie/4.184 Joules)= 96.1 calories===========
The change in temperature is 25 degrees Celsius, meaning it takes 22.48 joules per degree of change. The specific heat of iron is 0.449 J/g degree Celsius. This means that the mass of iron must be 50.07 grams
Water has a high specific heat capacity, which means it can absorb and release a large amount of heat without much change in temperature. This property allows water to help regulate Earth's climate by absorbing heat in the summer and releasing it in the winter.
The bomb calorimeter formula used to calculate the heat released during a chemical reaction is: q C x T where: q heat released (in joules) C calorimeter constant (in joules per degree Celsius) T change in temperature (in degrees Celsius)
8.200 J
q(joules) = mass * specific heat * change in temperature ( 8 kg = 8000 grams ) q = (8000 grams H2O)(4.180 J/gC)(70o C - 20o C) = 1.7 X 106 joules ============
One degree Fahrenheit is equal to 0.5556 degrees Celsius. To convert this temperature change to energy in joules, you would need to know the specific heat capacity of the substance in question. The formula to calculate the energy change in joules is Q = mcΔT, where Q is the energy change, m is the mass of the substance, c is the specific heat capacity, and ΔT is the temperature change in degrees Celsius.
E = mass x specific heat x Δ°T Δ°T = new temperature - original temperature where Δ°T is equal to temperature change (Celsius in this case). The specific heat of Al is 0.900 J/g°C. Before we proceed to find the quantity of heat in joules, we must first find the temperature change. To calculate the temperature change, we must subtract the original temperature from the new temperature. Δ°T = 50°C - 25°C = 25°C In order to find the quantity of heat (joules), we must multiply mass, specific heat, and the temperature change (calculated above). E = 40.0g x 0.900 J/g°C x 25°C = 900 Joules or 9.0 x 102 Joules
It takes 4.184 joules of energy to change the temperature of 1 gram of water by 1 degree Celsius.
Heat energy is typically measured in joules (J) or calories (cal). Degrees Celsius and degrees Fahrenheit are units of temperature, not energy.
q( in Joules ) = mass * specific heat * change in temperature [ convert temps--Tf = Tc(1.80) + 32 ] q = (40 g)(0.90 J/gC)(61.1o C - 22.8o C) = 1.4 X 103 Joules =============
The specific heat capacity of water is 4.184 J/g°C. The change in temperature is 35.5°C - 21°C = 14.5°C. Using the formula Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature, you can calculate that the heat required is approximately 1554.7 joules.
The specific heat capacity of water is 4.184 J/g°C. The change in temperature is 70°C - 20°C = 50°C. Using the formula Q = mcΔT, where Q is the energy, m is the mass, c is the specific heat capacity, and ΔT is the temperature change, we get Q = 74g * 4.184 J/g°C * 50°C = 15,535.2 Joules.
Approx 4974 Joules.
E = mass x specific heat x Δ°t (temperature change)------------------ Energyspecific heat * temperature change = massΔ°t = new temperature - original temperatureIn order to calculate the mass of water able to be heated, we must divide the given energy by the result of specific heat times temperature change. Before proceeding to do such, we must calculate the temperature change, as well as convert cal to joules. It is also important to know that water's specific heat is 4.184 J/g°C.1. Calculate temperature change.Δ°t = 100°C-25°CΔ°t= 75°C2. Convert kcal to joules (multiply kcal * 103 * 4.184 joules [J]). (kcal --> joules)Joules = 4.22 kcal x 103 cal x 4.184 J/g°C = 17656.48 Joules------------------------ 1 kcal ------ 1 cal3. Find mass.Mass = 17656.48J(4.184J/g°C * 75°C) = 56.3g
The amount of energy required to raise the temperature of 1 kg of water by 1 degree Celsius is approximately 4,186 Joules. Therefore, to raise the temperature by 2 degrees Celsius, you would need about 8,372 Joules of energy.