The melting point for lauric acid is about 45 degrees while it is 121 degrees for naphthol. So, in a mixture repeated cycles of slow warming and cooling should separate out lauric acid from naphthol. You can improve the efficiency by adding a dash of slightly acidic 70% isopropyl alcohol. This will deprotonate the lauric acid while maintaining the proton on naphthol during this process to enhance separation and purification of the two compounds. You could also flat-out distill the two products by maintaining the temperature of the solution at the boiling point of lauric acid to separate it from naphthol.
Benzophenone is soluble in cyclohexane, but a-naphthol is insoluble in cyclohexane. Therefore, you can dissolve the benzophenone in the cyclohexane, and then filter or decant for the a-naphthol.
You can add cyclohexane to the mixture. a-naphthol is insoluble in cyclohexane while lauric acid is soluble in cyclohexane.
Distillation, since the boiling pt of acetone is much higher.
== ==
benzophenone + NH3OHCl --> benzophenone oxime (+acid) ---> beckmann rearrangement --> benzanilide
Benzophenone is partially soluble in hexane. Benzophenone is polar, where as, hexane is nonpolar. "Like dissolves like."
From least to most polar: biphenyl >> benzophenone >> benzhydrol
The question here is asked in a slightly incorrect manner. Assuming I understand exactly what you meant to ask which is "In a reduction of Benzophenone is Diphenylmethanol created with a 1/1 molar ratio?" then the answer is yes they are. For every mole of benzophenone one mole of diphenylmethanol is created. Benzophenone is a reagent and diphenylmethanol is a product in a reduction of benzophenone reaction. However if you're referring to a reaction which creates BOTH diphenylmethanol and benzophenone as products, then you would need to provide the reagents that create the two.
4
benzophenone + NH3OHCl --> benzophenone oxime (+acid) ---> beckmann rearrangement --> benzanilide
Benzophenone is partially soluble in hexane. Benzophenone is polar, where as, hexane is nonpolar. "Like dissolves like."
From least to most polar: biphenyl >> benzophenone >> benzhydrol
The question here is asked in a slightly incorrect manner. Assuming I understand exactly what you meant to ask which is "In a reduction of Benzophenone is Diphenylmethanol created with a 1/1 molar ratio?" then the answer is yes they are. For every mole of benzophenone one mole of diphenylmethanol is created. Benzophenone is a reagent and diphenylmethanol is a product in a reduction of benzophenone reaction. However if you're referring to a reaction which creates BOTH diphenylmethanol and benzophenone as products, then you would need to provide the reagents that create the two.
The carbonyl group of the benzophenone acts as a hydrogen bond acceptor with the alcohol group of methanol.
Benzophenone prevents ultraviolet light from damaging colors and scents in products. Without the use of benzophenone some products would have to be shipped in black or dark packaging for protection.
water.
Yes, benzophenone is soluble in ethanol, not insoluble as previously stated (trust me on this previous editor I work with the stuff).
seperate cotton from the cotton seeds and improved slavery
Benzophenone dissolves non-polar molecules better than water. It is commonly used in preparing pure and anhydrous solvents because it removes moisture and oxygen unlike water.
That way they could break free from britian and be their own seperate nation.
4