You need the Ksp of copper sulphide. From that you can use the equation for solubility product - Ksp = [Cu2+].[S-] where the Cu2+ term becomes 25M.
The reaction between CuCl2 (copper(II) chloride) and H2S (hydrogen sulfide) is a double displacement reaction. The balanced chemical equation is: CuCl2 + H2S -> CuS + 2HCl The products formed are CuS (copper(II) sulfide) and 2HCl (hydrochloric acid).
The proper formula unit for the combination of copper(II) ions and chloride ions is CuCl2. In this compound, each copper ion carries a 2+ charge (Cu^2+) and each chloride ion carries a 1- charge (Cl^-). The subscript 2 in the formula indicates that two chloride ions are needed to balance the charge of one copper(II) ion.
First multiply .131ml and 7.95M to get the moles of Cucl2. (You will need this later) Then find the moles per 49.5ml diluted solution. (6.1g divided my molar mass) Then set both equal to each other Original mol/X = Diluted mol/49.5ml and solve for X This should work
The anion in CuCl2 is chloride (Cl-).
The complete ionic equation for the reaction between copper(II) sulfate and barium chloride is: Cu^2+(aq) + SO4^2-(aq) + 2Ba^2+(aq) + 2Cl^-(aq) → BaSO4(s) + CuCl2(aq)
Copper(II) chloride is already a compound; its formula is CuCl2
The chemical formula (not equation) of copper(II) chloride is CuCl2.
The reaction between CuCl2 (copper(II) chloride) and H2S (hydrogen sulfide) is a double displacement reaction. The balanced chemical equation is: CuCl2 + H2S -> CuS + 2HCl The products formed are CuS (copper(II) sulfide) and 2HCl (hydrochloric acid).
The solubility of CuCl2 in water is 75,7 g/100 mL at 25 0C.
The Transition metals can have variable charges depending on what they are bonded to. In this example the Copper atom is deficient by two electrons one for each Chlorine atom.
They are identical - bonding two elements to form a binary compound. The only difference is that copper can be found as copperII or copperIV so it's correct to specify which one, that's all. Save with Pb (lead) and other unique metals/nonmetals.
The proper formula unit for the combination of copper(II) ions and chloride ions is CuCl2. In this compound, each copper ion carries a 2+ charge (Cu^2+) and each chloride ion carries a 1- charge (Cl^-). The subscript 2 in the formula indicates that two chloride ions are needed to balance the charge of one copper(II) ion.
In the chemical formula CuCl2 it is obvious for a neutral ionic substance that copper has a +2 charge, since Cl only comes in -1 charge, but in the stock name of copper chloride, it is unclear whether it is CuCl2 you are talking about or CuCl, which has a +1 Copper, thus in the name, the charge of the metal is differentiated by the roman numeral in parenthesis after the metal. This stock system (using numerals) is much easier to read than the previous traditional system of naming the higher charge metal with the -ic ending and the lower charged metal with the -ous ending, where CuCl2 and CuCl would be cupric chloride and cuprous chloride, respectively.
First multiply .131ml and 7.95M to get the moles of Cucl2. (You will need this later) Then find the moles per 49.5ml diluted solution. (6.1g divided my molar mass) Then set both equal to each other Original mol/X = Diluted mol/49.5ml and solve for X This should work
The anion in CuCl2 is chloride (Cl-).
CuO + 2HCL - CuCl2 + H2O
The complete ionic equation for the reaction between copper(II) sulfate and barium chloride is: Cu^2+(aq) + SO4^2-(aq) + 2Ba^2+(aq) + 2Cl^-(aq) → BaSO4(s) + CuCl2(aq)