HCl + NaOh -> H2O + NaCl
No coefficients are needed because the number of atoms are present on each side by default. Mixing an acid and a base always makes water and a salt, thus the sodium chloride.
The balanced equation for Na2O + H2O → 2 NaOH is: Na2O + H2O → 2 NaOH
The balanced equation is: CaCl2 + H2CO3 -> CaCO3 + 2HCl. So, the coefficient needed is 2 in front of HCl to balance the reaction.
To balance the reaction between NaOH and H2SO4, you first write out the unbalanced equation: NaOH + H2SO4 -> Na2SO4 + H2O. To balance it, you need to ensure the same number of atoms of each element on both sides of the equation by adjusting the coefficients. In this case, you would need to put a coefficient of 2 in front of NaOH to balance the equation: 2NaOH + H2SO4 -> Na2SO4 + 2H2O.
When NaHCO3 is combined with CaCl2 and H2O, a reaction will occur. However, the specific products depend on the conditions of the reaction - typically, NaHCO3 will react with CaCl2 to form NaCl, CaCO3, and H2O.
The balanced equation is 2Na + CaCl2 → 2NaCl + Ca. This is achieved by ensuring the same number of atoms of each element appear on both sides of the equation. In this case, balancing the equation required doubling the coefficient of NaCl and Ca.
Ca + Cl2 ---> CaCl2
2hcl
2Na + 2H2O -> H2 + 2NaOH
The balanced equation for Na2O + H2O → 2 NaOH is: Na2O + H2O → 2 NaOH
2Na + 2H2O -------> 2NaOH + H2
P + Na(OH) + H20 = NaH2PO2 + PH3
(Don't forget to balance it) The precipitate here has to be 2NaCl, as Ca(CO3)2 technically dissolves.
The balanced equation is: CaCl2 + H2CO3 -> CaCO3 + 2HCl. So, the coefficient needed is 2 in front of HCl to balance the reaction.
The chemical reaction is:H3PO4 + 3 NaOH + Na3PO4 + 3 H2O
To balance the reaction between NaOH and H2SO4, you first write out the unbalanced equation: NaOH + H2SO4 -> Na2SO4 + H2O. To balance it, you need to ensure the same number of atoms of each element on both sides of the equation by adjusting the coefficients. In this case, you would need to put a coefficient of 2 in front of NaOH to balance the equation: 2NaOH + H2SO4 -> Na2SO4 + 2H2O.
In the balanced reaction between calcium chloride (CaCl2) and sodium hydroxide (NaOH) to form calcium hydroxide (Ca(OH)2) and sodium chloride (NaCl), the stoichiometry indicates that 1 mole of CaCl2 reacts with 2 moles of NaOH to produce 1 mole of Ca(OH)2. Therefore, the best conversion factor to use when calculating the number of moles of calcium hydroxide formed from each mole of sodium hydroxide is ( \frac{1 , \text{mol Ca(OH)}_2}{2 , \text{mol NaOH}} ). This factor shows that for every 2 moles of NaOH used, 1 mole of Ca(OH)2 is produced.
When NaHCO3 is combined with CaCl2 and H2O, a reaction will occur. However, the specific products depend on the conditions of the reaction - typically, NaHCO3 will react with CaCl2 to form NaCl, CaCO3, and H2O.