2 ci + 2 ki = 2 kci + i2
The reaction is:Cl2 + 2 Ki = 2 KCl + I2
Ki + i2 --> ki3
Potassium iodide does not react with water; it only dissolves. The equation for this is KI(s) --> K+(aq) + I-(aq).
Cr2O72- + 6 I- + 14 H+ → 2 Cr3+ + 3 I2 + 7 H2O
2 ci + 2 ki = 2 kci + i2
The reaction is:Cl2 + 2 Ki = 2 KCl + I2
Pretty sure it's KI cuz k+ and I- make KI I2 is I- as an ion
I is replaced by Cl.So KCl and I2 is formed.
Cl2(g) + 2KI --> 2KCl(aq) + I2(s)
Literally, the correct formula for potassium and iodine at standard temperature and pressure would be " K and I2". The formula for the compound formed between potassium and iodine, however, is KI.
182.88
Ki + i2 --> ki3
H2O2 + 2 KI --> 2 KOH + I2
The chemical reaction is:2 K + I2 = 2 KI
Iodine (I2) reacts with iodide (I-) to form triiodide ion (I3-). Although I2 is insoluble in water, I3-is very soluble, so adding KI will pull I2into solution is I3-.
Potassium iodide does not react with water; it only dissolves. The equation for this is KI(s) --> K+(aq) + I-(aq).