Start with the most complex molecule. In this case its Cu2O from the products side, and leave the oxygen for last. Follow these steps using the Cu2O molecule as your guide. 1) Place a 2 in front of CuS on the reactants side. This will balance the copper atoms. 2CuS + O2 --> Cu2O + SO2 2) Next balance the sulfur atoms by placing a 2 in front of SO2 on the products side. 2CuS + O2 --> Cu2O + 2SO2 3) Now, the only atoms left to balance are the oxygen. There are a total of 5 oxygen atoms on the products side and 2 on the reactants side. Fix this by placing a 2.5 in front of O2 molecule. 2CuS + 2.5O2 --> Cu2O + 2SO2 4) There is one more step to finish balancing this equation. There cannot be any partial molecules in a balanced chemical equation. To fix the partial molecule of O2, multiply the entire equation by the smallest number that gives all whole numbers for the coefficients. Thus, multiply this equation by 2. 4CuS + 5O2 --> 2Cu2O + 4SO2 This is the final balanced equation.
2 CuS + 3 O2 --> 2 CuO + 2 SO2
OKAY THE ANSWER IS REALLY EASY_ H2SO4 + 2NaOH----> 2H2O + Na2SO4
The reaction of sodium hydroxide with copper sulfate produces sodium sulfate and copper hydroxide. The reaction is balanced as NaOH + CuSO4 = Cu(OH)2 + Na2SO4.
Nooooo!!! It's na2so4 + h2so3.
It's a double change
The equation is:
2 KOH + Cu(NO3)2 = 2 KNO3 + Cu(OH)2(s)
2NaOH + H2CO3 → Na2CO3 + 2H2O
H2SO4 + NaOH -> Na2SO4 + H2O
The general reaction for acid-base reactions is as follows: Acid + Base = Salt + Water In this case H2SO4 + 2 NaOH --> Na2SO4 + 2 H2O Actually: H2SO4 (aq) + NaOH (aq) ---> NaHSO4 (aq) + H2O(l) NaHSO4 (aq) + NaOH (aq) ---> Na2SO4 (aq) + H2O(l)
sulfuric acid + sodium hydroxide ---> sodium sulfate + water
Sulfuric acid plus sodium hydroxide gives sodium sulfate plus water.
Both NaOH and H2SO4 have no colour, even not after complete reaction (Na2SO4 and H2O are also colourless)
HCl + NaOH --> Na2SO4 + H2O You're missing something there... There's sulfur in the products but not in the reactants. And chloride in the reactants but not in the products... More likely you meant HCl + NaOH --> NaCl + H2O Which is already balanced.
The general reaction for acid-base reactions is as follows: Acid + Base = Salt + Water In this case H2SO4 + 2 NaOH --> Na2SO4 + 2 H2O Actually: H2SO4 (aq) + NaOH (aq) ---> NaHSO4 (aq) + H2O(l) NaHSO4 (aq) + NaOH (aq) ---> Na2SO4 (aq) + H2O(l)
sulfuric acid + sodium hydroxide ---> sodium sulfate + water
Sulfuric acid plus sodium hydroxide gives sodium sulfate plus water.
Both NaOH and H2SO4 have no colour, even not after complete reaction (Na2SO4 and H2O are also colourless)
HCl + NaOH --> Na2SO4 + H2O You're missing something there... There's sulfur in the products but not in the reactants. And chloride in the reactants but not in the products... More likely you meant HCl + NaOH --> NaCl + H2O Which is already balanced.
This reaction is:2 NaOH + H2SO4 = Na2SO4 + 2 H2O
Na2O + H2O ---------> 2NaOH
The net ionic equation for NaOH and Na2SO4 when they form a precipitate is simple. It will contain only the atoms that participate in the reaction. Both of these compounds are soluble.
This is a neutralization reaction:2 NH4OH + H2SO4 = (NH4)2SO4 + 2 H2O
my balance sheet does not balance why?
This equation is Na2CO3 + 2 HCl -> 2 NaCl + CO2 (gas) + H2O.
NaOH + HCl ----> NaCl + H2O