How do you balance NH4 2SO4 NaOH------- NH3 H2O Na2SO4?

Answer 1

Start with the most complex molecule. In this case its Cu2O from the products side, and leave the oxygen for last. Follow these steps using the Cu2O molecule as your guide. 1) Place a 2 in front of CuS on the reactants side. This will balance the copper atoms. 2CuS + O2 --> Cu2O + SO2 2) Next balance the sulfur atoms by placing a 2 in front of SO2 on the products side. 2CuS + O2 --> Cu2O + 2SO2 3) Now, the only atoms left to balance are the oxygen. There are a total of 5 oxygen atoms on the products side and 2 on the reactants side. Fix this by placing a 2.5 in front of O2 molecule. 2CuS + 2.5O2 --> Cu2O + 2SO2 4) There is one more step to finish balancing this equation. There cannot be any partial molecules in a balanced chemical equation. To fix the partial molecule of O2, multiply the entire equation by the smallest number that gives all whole numbers for the coefficients. Thus, multiply this equation by 2. 4CuS + 5O2 --> 2Cu2O + 4SO2 This is the final balanced equation.
2 CuS + 3 O2 --> 2 CuO + 2 SO2

Answer 2

To balance the equation, start by balancing the elements present. In this case, you have 2 N atoms on the left side from NH4, 1 N atom in NH3 on the right side. Balance the N atoms by putting a coefficient of 2 in front of NH3. This will give you 2 N atoms on both sides. Then proceed to balance the other elements accordingly.

Answer 3

OKAY THE ANSWER IS REALLY EASY_ H2SO4 + 2NaOH----> 2H2O + Na2SO4

Answer 4

The reaction of sodium hydroxide with copper sulfate produces sodium sulfate and copper hydroxide. The reaction is balanced as NaOH + CuSO4 = Cu(OH)2 + Na2SO4.

Answer 5

Nooooo!!! It's na2so4 + h2so3.

It's a double change

Answer 6

(NH4)2SO4 + 2NaOH-------> 2NH3 + 2H2O + Na2SO4

Answer 7

The equation is:
2 KOH + Cu(NO3)2 = 2 KNO3 + Cu(OH)2(s)

Answer 8

2NaOH + H2CO3 → Na2CO3 + 2H2O

Answer 9

H2SO4 + NaOH -> Na2SO4 + H2O