Mg(OH)2 + 2HNO3 -> Mg(NO3)2 + 2H2O
Like that.
Remember, NO3 is 1- and Mg is 2+, so you need 2 NO3 to fo with 1 Mg.
2 Fe2O3 + 12 HNO3 -> 4 Fe(NO3)3 + 6 H2O
HNO3 + H2O -> H3O + NO3 is very acidic. This is because HNO3 is a strong acid and almost completely dissociates in water
4(NH3) + 5(O2) --> 4NO + 6(H20)
Cu + 4HNO3 ----->Cu(NO3)2 + 2NO2 + 2H20
HNO3 + MgCO3 --> H2O + CO2 + Mg(NO3)2 (Products are water, carbon dioxide and magnesium nitrate)
Cu + HNO3 = Cu(NO3)2 + NO + H2O
2 Fe2O3 + 12 HNO3 -> 4 Fe(NO3)3 + 6 H2O
HNO3 + H2O -> H3O + NO3 is very acidic. This is because HNO3 is a strong acid and almost completely dissociates in water
4(NH3) + 5(O2) --> 4NO + 6(H20)
Cu + 4HNO3 ----->Cu(NO3)2 + 2NO2 + 2H20
HNO3 + MgCO3 --> H2O + CO2 + Mg(NO3)2 (Products are water, carbon dioxide and magnesium nitrate)
Hno3 -----------h+ + (no3)-1
HNO3 + NH3 =NH4NO3 is not a precipitation reaction, ALL(NO3-) nitrates are soluble even in water.
The chemical reaction is:Fe(OH)3 + 3 HNO3 = Fe(NO3)3 + 3 H2O
What is the balanced equation for the reaction of calcuim hydroxide and nitric acid? . Ca(OH)2 .+..HNO3..=..Ca+2(NO3-1)..+.. H+1OH-1 (water) . Balance charges Ca(OH)2 .+..HNO3..=..Ca(NO3)2..+.. HOH .balance atoms Ca(OH)2… +…HNO3....=..Ca(NO3)2..+.. HOH Balance OH's Ca(OH)2….+.. HNO3….=.. Ca(NO3)2..+..2HOH . Balance H's Ca(OH)2….+..2HNO3..=.. Ca(NO3)2..+..2HOH . Done!!
HNO3 + H2O ---> (H3O)+ + (NO3)- Only thing i dont remember is if the arrow is double (<-->). If the acid is potent then the arrow is single. But i think in this case it is potent.
CaCO3 + HNO3 --> Ca(NO3)2 + <H2CO3> <H2O + CO2> The liquid which once was cloudy will turn it's coloration back to transparent