Mg(OH)2 + 2HNO3 -> Mg(NO3)2 + 2H2O
Like that.
Remember, NO3 is 1- and Mg is 2+, so you need 2 NO3 to fo with 1 Mg.
2 Fe2O3 + 12 HNO3 -> 4 Fe(NO3)3 + 6 H2O
4(NH3) + 5(O2) --> 4NO + 6(H20)
The conjugate base for the equation HNO3 + NaOH -> H2O + NaNO3 is the nitrate ion (NO3-), which is formed when the strong acid HNO3 donates a proton to water (H2O) to form the weak conjugate base NO3-.
The reaction you provided is the dissociation of nitric acid (HNO3) in water. In this reaction, HNO3 donates a proton to water, forming hydronium ions (H3O+) and nitrate ions (NO3-), indicating that HNO3 is an acid.
Nitric acid (HNO3) and calcium hydroxide (Ca[OH]2) react to form calcium nitrate (Ca[NO3]2) and water (H2O).
Cu + HNO3 = Cu(NO3)2 + NO + H2O
2 Fe2O3 + 12 HNO3 -> 4 Fe(NO3)3 + 6 H2O
4(NH3) + 5(O2) --> 4NO + 6(H20)
The conjugate base for the equation HNO3 + NaOH -> H2O + NaNO3 is the nitrate ion (NO3-), which is formed when the strong acid HNO3 donates a proton to water (H2O) to form the weak conjugate base NO3-.
The reaction you provided is the dissociation of nitric acid (HNO3) in water. In this reaction, HNO3 donates a proton to water, forming hydronium ions (H3O+) and nitrate ions (NO3-), indicating that HNO3 is an acid.
Nitric acid (HNO3) and calcium hydroxide (Ca[OH]2) react to form calcium nitrate (Ca[NO3]2) and water (H2O).
It is a dissociation reaction: HNO3---------H+ + (NO3)-
The balanced chemical equation for the reaction between nitric acid (HNO3) and antimony (Sb) is: 6 HNO3 + 2 Sb → 2 Sb(NO3)3 + 3 H2O
The balanced chemical equation for the dissociation of nitric acid (HNO3) in water is: HNO3(aq) -> H+(aq) + NO3-(aq)
The equation is:H+ + (NO3)- + Na+ + (OH)- = (NO3)- + Na+ + H2O (2 H+ OH-)
Cu + 4HNO3 ----->Cu(NO3)2 + 2NO2 + 2H20
When CaCO3 is added to HNO3, a chemical reaction occurs where CaCO3 reacts with HNO3 to produce Ca(NO3)2, CO2, and H2O. This reaction is a double displacement reaction where the calcium ions in CaCO3 switch places with the nitrate ions in HNO3.