N2h4 + 2h2o2 = n2 + 4h2o
2 Fe2O3 + 12 HNO3 -> 4 Fe(NO3)3 + 6 H2O
The conjugate base for the equation HNO3 + NaOH -> H2O + NaNO3 is the nitrate ion (NO3-), which is formed when the strong acid HNO3 donates a proton to water (H2O) to form the weak conjugate base NO3-.
4(NH3) + 5(O2) --> 4NO + 6(H20)
The balanced chemical equation for the dissociation of nitric acid (HNO3) in water is: HNO3(aq) -> H+(aq) + NO3-(aq)
The equation is:H+ + (NO3)- + Na+ + (OH)- = (NO3)- + Na+ + H2O (2 H+ OH-)
Cu + HNO3 = Cu(NO3)2 + NO + H2O
2 Fe2O3 + 12 HNO3 -> 4 Fe(NO3)3 + 6 H2O
The conjugate base for the equation HNO3 + NaOH -> H2O + NaNO3 is the nitrate ion (NO3-), which is formed when the strong acid HNO3 donates a proton to water (H2O) to form the weak conjugate base NO3-.
The balanced chemical equation for the dissociation of nitric acid (HNO3) in water is: HNO3(aq) -> H+(aq) + NO3-(aq)
4(NH3) + 5(O2) --> 4NO + 6(H20)
The equation is:H+ + (NO3)- + Na+ + (OH)- = (NO3)- + Na+ + H2O (2 H+ OH-)
The balanced chemical equation for the reaction between nitric acid (HNO3) and antimony (Sb) is: 6 HNO3 + 2 Sb → 2 Sb(NO3)3 + 3 H2O
Cu + 4HNO3 ----->Cu(NO3)2 + 2NO2 + 2H20
The balanced chemical equation for the reaction of magnesium oxide (MgO) and nitric acid (HNO3) is: MgO + 2HNO3 → Mg(NO3)2 + H2O.
To balance the chemical equation Mg(OH)2 + HNO3 → Mg(NO3)2 + H2O, start by balancing the elements other than hydrogen and oxygen. Balance Mg first: Mg(OH)2 + 2HNO3 → Mg(NO3)2 + H2O. Then balance hydrogen by adding 2 molecules of water: Mg(OH)2 + 2HNO3 → Mg(NO3)2 + 2H2O. Finally, balance oxygen by adding 2 more nitric acid molecules: Mg(OH)2 + 2HNO3 → Mg(NO3)2 + 2H2O.
Nitric acid: HNO3 (acid) Sodium hydroxide: NaOH (base) This is therefore an acid-base reaction. Acid + Base --> Salt + Water Therefore: HNO3 + NaOH --> NaNO3 + H20 Or: Nitric acid + Sodium hydroxide --> Sodium Nitrate + Water
The balanced chemical equation is Ca(OH)2 + Na2CO3 + 2HNO3 → Ca(NO3)2 + 2NaOH + CO2 + H2O