2 Ag2O --> 4Ag + O2
The balanced equation for the decomposition of silver oxide (Ag2O) when heated is: 2 Ag2O(s) -> 4 Ag(s) + O2(g)
The decomposition of silver oxide (Ag2O) produces silver metal (Ag) and oxygen gas (O2) as the products. The balanced chemical equation for this decomposition reaction is: 2Ag2O(s) -> 4Ag(s) + O2(g).
Given 2Ag2O(s) --> 4Ag(s) + O2(g), and 5.50g of reactant, you get 5.5/232gmol-1 (molar mass reactant)=0.0237mol, times(2) (stoichiometric ratio)=0.0474mol Ag, times(108gmol-1) (atomic mass silver)=approx. 5.12g silver.
Na2O is ionic and consists of Na+ and O2- ions.
Ag2O is silver oxide, an ionic compound composed of silver cations (Ag+) and oxide anions (O2-). It is a dark brown solid that is commonly used as a reagent in organic synthesis.
The balanced equation for the decomposition of silver oxide (Ag2O) when heated is: 2 Ag2O(s) -> 4 Ag(s) + O2(g)
The balanced chemical equation for the decomposition of silver(I) oxide (Ag2O) is 2Ag2O -> 4Ag + O2.
The decomposition of silver oxide (Ag2O) produces silver metal (Ag) and oxygen gas (O2) as the products. The balanced chemical equation for this decomposition reaction is: 2Ag2O(s) -> 4Ag(s) + O2(g).
Given 2Ag2O(s) --> 4Ag(s) + O2(g), and 5.50g of reactant, you get 5.5/232gmol-1 (molar mass reactant)=0.0237mol, times(2) (stoichiometric ratio)=0.0474mol Ag, times(108gmol-1) (atomic mass silver)=approx. 5.12g silver.
Because Ag2O (as oxidator) is more reactive than FeO, so Fe (as reductor) can abstract the oxide O (O2-) from Ag2O according to electrochemical series (which says: Ag is less reactive to oxygen than Fe, Ag is a more 'noble' metal)Fe + Ag2O --> FeO + 2Ag
First we have to figure out which species is oxidized and which is reduced and balance it in acid solution. On the left side, Ag has an oxidation number of 0 (it is an uncombined element). On the right side, Ag is +1. Why? Ag = +1 + 2CN- = -2 ----------------------------- Ag(CN) ion charge = -1 Note that oxygen on the left side also has an oxidation number of 0 for the same reason as Ag. But on the right side of the equation, it has formed H2O and has a charge of -2. CN- is really a spectator ion (isn't oxidized or reduced) so we can ignore it for now. Let's balance each half-reaction. I'm using = as an arrow sign. Oxidation: Ag = Ag+ + e- (done) Reduction: O2 = H2O Put a 2 in front of H2O O2 = 2H2O to balance oxygen Put 4H+ on the left side O2 + 4H+ = 2H2O to balance hydrogen Put 4e- on the left to O2 + 4H+ + 4e- = 2H2O To add the oxidation and reduction reactions together, I need to multiply the oxidation reaction by 4 so its electrons will cancel with the four that are in the reduction reaction. Doing that you get 4Ag + O2 + 4H+ = 4Ag+ + 2H2O In alkaline solution, you find the H+ above and add an equal number of OH- to BOTH sides of the equation: The 4H+ + 4OH- give 4 H2O. 4Ag + O2 + 4H+ = 4Ag+ + 2H2O +4OH- + 4OH- --------------------------------------... 4H2O If I delete two H2O from each side I get: 4Ag + O2 + 2H2O = 4Ag+ + 4OH- Finally, I can add 2CN- to each side for this: 4Ag + O2 + 2H2O + 8CN- = 4Ag(CN)- + 4OH-
Silver oxide --> silver and (+) oxygenAg2O --> Ag2 + O2BALANCED =2Ag2O --> 2Ag2 + O2
what is ag2o
Na2O is ionic and consists of Na+ and O2- ions.
Ag2O is silver oxide, an ionic compound composed of silver cations (Ag+) and oxide anions (O2-). It is a dark brown solid that is commonly used as a reagent in organic synthesis.
The combustion of silver oxide produces silver metal and oxygen gas. The chemical equation for this reaction is: 2Ag2O(s) → 4Ag(s) + O2(g). This is a redox reaction where silver oxide is reduced to silver metal and oxygen is oxidized to form oxygen gas.
This simple equation is: 2H2 + O2 = 2H2O