To calculate the moles of argon present at standard temperature and pressure (STP), you can use the ideal gas law equation PV = nRT. At STP, the pressure is 1 atm and the temperature is 273 K. If you know the volume of the argon gas, you can rearrange the equation to solve for moles, n.
At STP, 1 mole of any gas occupies 22.4 L. Therefore, in a 5L sample of argon at STP, there would be 5/22.4 moles of argon, which is approximately 0.223 moles.
Argon is a gas at STP. It becomes a liquid below -186oC and solid below -190oC at StP
By using the ideal gas law, at STP (standard temperature and pressure), 1 mole of any ideal gas occupies 22.4 liters. Therefore, in 4.00 liters of CO2 gas at STP there would be 4.00/22.4 = 0.179 moles of CO2 present.
To answer this, we must first know what STP is. STP (Standard Temperature and Pressure) is when the environment is at the following:0oC1 Atmosphere of Pressure (101.325 kPa)To figure out any missing units in a gas equation, we use the Ideal Gas Law, PV=nRT.'P' is pressure in kPa'V' is volume in litres or dm3'n' is the number of mol'R' is the gas constant = 8.314'T' is temperature in kelvinTo work out the number of mol, we substitute in the calues we have and solve for n. This gives us 101.325kPa*5.6dm3=n*8.314*273K. Therefore, n=0.25 mol.Alternatively, we could simply use the fact that 1 mol of any gas at STP takes up 22.4 litres. So 5.6/22.4 leaves us with 0.25 mol.
At STP (Standard Temperature and Pressure), 1 mole of any gas occupies 22.4 liters. Therefore, 15 liters of oxygen at STP would be equivalent to 15/22.4 = 0.67 moles.
At STP, 1 mole of any gas occupies 22.4 L. Therefore, in a 5L sample of argon at STP, there would be 5/22.4 moles of argon, which is approximately 0.223 moles.
8,4 liters of nitrous oxide at STP contain 2,65 moles.
The molar volume of any ideal gas at standard temperature and pressure (STP) is 22.4 L/mol. Converting 39.6 dm3 to liters gives 39.6 L. To find the mass of argon gas, we calculate the number of moles using the ideal gas equation (PV = nRT) and then multiply by the molar mass of argon.
The answer is 0,2675 moles.
Assuming ideal behaviour, 1 mole of any gas occupies 22.4L at STP. So, moles of 10L = 10/22.4 moles = 0.4464 moles
Argon is a gas at STP. It becomes a liquid below -186oC and solid below -190oC at StP
By using the ideal gas law, at STP (standard temperature and pressure), 1 mole of any ideal gas occupies 22.4 liters. Therefore, in 4.00 liters of CO2 gas at STP there would be 4.00/22.4 = 0.179 moles of CO2 present.
To answer this, we must first know what STP is. STP (Standard Temperature and Pressure) is when the environment is at the following:0oC1 Atmosphere of Pressure (101.325 kPa)To figure out any missing units in a gas equation, we use the Ideal Gas Law, PV=nRT.'P' is pressure in kPa'V' is volume in litres or dm3'n' is the number of mol'R' is the gas constant = 8.314'T' is temperature in kelvinTo work out the number of mol, we substitute in the calues we have and solve for n. This gives us 101.325kPa*5.6dm3=n*8.314*273K. Therefore, n=0.25 mol.Alternatively, we could simply use the fact that 1 mol of any gas at STP takes up 22.4 litres. So 5.6/22.4 leaves us with 0.25 mol.
At STP (Standard Temperature and Pressure), 1 mole of any gas occupies 22.4 liters. Therefore, 15 liters of oxygen at STP would be equivalent to 15/22.4 = 0.67 moles.
Argon is a gas at STP.
1 mole occupies 22.414 liters So, 3.30 moles will occupy 73.966 liters.
To calculate the moles of C3H4 consumed, we can use the ideal gas law equation PV = nRT at STP conditions (standard temperature and pressure). Since the volume (V) is 5.6 L, and at STP conditions 1 mole of gas occupies 22.4 L, we can calculate the number of moles of C3H4 consumed as (5.6 L / 22.4 L/mol) = 0.25 moles.