Molecular mass of Cu(NO3)2 :-63.54+2(14+16x3)=187.54g/mol Number of moles=1.56/187.54=0.008318mol
The concentration is 2 M.
No. It is a chemical change (chemical reaction) in which the products are different from the reactants. The balanced chemical equation is Cu(NO3)2+2NH4OH-->Cu(OH)2+2NH4NO3, which means one mole of copper(II) nitrate plus two moles of ammonium hydroxide produce one mole of copper(II) hydroxide plus two moles of ammonium nitrate.
100mg of salt per ml is 100,000mg salt/L, i.e. 100g per litre. The molecular mass of copper II nitrate is 187.556g/mol. Divide weight by molecular mass to give you moles of 0.5332. This is already in litres, so it is 0.5332 molar (M)
Number of Moles = concentration * volume (in litres)
1 mole of Copper has a mass of 63.546 g. So, 14.5 moles will be 14.5 times that amount. Do the math.
Avodagro's Number, which is defined as the number of molecules in one mole of a covalent compound or one formula unit of an ionic compound such as copper (II) nitrate, is about 6.022 X 1023. Therefore the number of moles asked in the question is (2.4 X 1024)/(6.022 X 1023) or 4.0 moles, to the justified number of significant digits.
9 g anhydrous magnesium nitrate = 0,061 mol
When 3 moles Cu react 3 moles of copper nitrate are obtained.
The concentration is 2 M.
The number of copper atoms is 79,49.10e23.
The concentration is 2 M.
The concentration is 2 mol/L.
No. It is a chemical change (chemical reaction) in which the products are different from the reactants. The balanced chemical equation is Cu(NO3)2+2NH4OH-->Cu(OH)2+2NH4NO3, which means one mole of copper(II) nitrate plus two moles of ammonium hydroxide produce one mole of copper(II) hydroxide plus two moles of ammonium nitrate.
100mg of salt per ml is 100,000mg salt/L, i.e. 100g per litre. The molecular mass of copper II nitrate is 187.556g/mol. Divide weight by molecular mass to give you moles of 0.5332. This is already in litres, so it is 0.5332 molar (M)
Calcium Nitrtae is Ca(NO3)2 and so there are two moles of nitrate per mole of calcium nitrate. Thus there are 2 x 2.50 = 5.0 moles of nitrate present.
Number of Moles = concentration * volume (in litres)
Mass = moles x formula mass Mass = 0.139 x atomic mass of copper (63.5) Mass = 8.83g