It is supposed to be mol/dm-3
Actually, 1 dm cube is the same as 1 litre.
Therefore, there is no need of conversion. Both are the same.
98 g per dm3 would be 1 molar - so 49 g would be 0.5 molar , so 4.9 g is 0.05 mol per dm3 or 0.05 mol.dm-3
right i dont know this 4 sure but because u want a 0.1 mol/dm3 and u only need 100cm3 u will need 0.01mols of copper sulfate to dilute in 100cm3. soo now u have a solution that is 0.01mols per 100cm3 or 0.1 mols per 1000cm3 (dm3)
1 mol is the equivalent of 24,000cm3 So, Moles = Value is cm3 (divided by) 24,000
In pure water, the concentration of H3O plus (hydronium ion, H3O+) is 1.0 x 10^-7 mol/L and the concentration of OH- (hydroxide ion) is also 1.0 x 10^-7 mol/L. This represents a balanced state of neutrality.
A liter is equal to a dm3. So, we have 3,292 dm3 solution. We need the amount of the NaCl. It is m/M -> 17,62 / 58,5 -> approx. 0,3012 mol. So, the molarity is 0,3012 / 3,292 -> 0,0915 mol dm-3 .
98 g per dm3 would be 1 molar - so 49 g would be 0.5 molar , so 4.9 g is 0.05 mol per dm3 or 0.05 mol.dm-3
No.
right i dont know this 4 sure but because u want a 0.1 mol/dm3 and u only need 100cm3 u will need 0.01mols of copper sulfate to dilute in 100cm3. soo now u have a solution that is 0.01mols per 100cm3 or 0.1 mols per 1000cm3 (dm3)
1 liter is 1 dm3
1 mol is the equivalent of 24,000cm3 So, Moles = Value is cm3 (divided by) 24,000
100cm = 10 dm = 1m 1000 dm3 = 1 m3 ---> 786 dm3 = 0.786 m3
kilolitres are 1000 litres, 1 dm3 = 1 litre so multiply by 1000
In pure water, the concentration of H3O plus (hydronium ion, H3O+) is 1.0 x 10^-7 mol/L and the concentration of OH- (hydroxide ion) is also 1.0 x 10^-7 mol/L. This represents a balanced state of neutrality.
To convert dm3 (cubic decimeters) to m2 (square meters), you need to consider the difference in dimensions. Cubic decimeters measure volume, while square meters measure area. Since volume and area are different concepts, direct conversion is not possible. You would need additional information, such as the height or depth of the object, to convert dm3 to m2.
A liter is equal to a dm3. So, we have 3,292 dm3 solution. We need the amount of the NaCl. It is m/M -> 17,62 / 58,5 -> approx. 0,3012 mol. So, the molarity is 0,3012 / 3,292 -> 0,0915 mol dm-3 .
The reaction : Mg + O2-----------> MgO The balanced reaction : 2 Mg + O2-----------> 2 MgO that is 2 moles of Mg reacts with one mole of oxygen gas. moles of Mg reacted = 12 g / 24 g mol-1=0.5 mol. Thus the no. of mol of O2 reacted = 0.5 mol /2 =0.25 mol If the gas is at standard temperature and pressure, then Volume of 1 mol of O2 gas = 22.4 dm3 Volume of 0.25 mol of O2 gas = 22.4 x 0.25 dm3= 5.6 dm3 the volume of oxygen that will be used to react completely with 12 g Mg =5.6 dm3 (provided that the gas is at the standard conditions.)
1 decimetre cubed = 1 litre.