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What is the volume of oxygen that will be used by 12g of Mg to be completely converted into MgO?
The reaction : Mg + O2-----------> MgO
The balanced reaction : 2 Mg + O2-----------> 2 MgO
that is 2 moles of Mg reacts with one mole of oxygen gas.
moles of Mg reacted = 12 g / 24 g mol-1=0.5 mol.
Thus the no. of mol of O2 reacted = 0.5 mol /2 =0.25 mol
If the gas is at standard temperature and pressure, then
Volume of 1 mol of O2 gas = 22.4 dm3
Volume of 0.25 mol of O2 gas = 22.4 x 0.25 dm3= 5.6 dm3
the volume of oxygen that will be used to react completely with 12 g Mg =5.6 dm3 (provided that the gas is at the standard conditions.)
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