in plastic containers or glass containers
To prepare a 0.005 M solution of H2SO4 with pH 4, you can first calculate the concentration of H+ ions needed to achieve a pH of 4. Then, use the dissociation of H2SO4 to determine the amount of H2SO4 needed to provide that concentration of H+ ions. Finally, dilute the calculated amount of H2SO4 with water to reach the desired volume of the solution.
To prepare 0.02N H2SO4 from 0.1N H2SO4, you can dilute the 0.1N H2SO4 by adding a calculated amount of water. To calculate the dilution factor, you can use the formula: C1V1 = C2V2, where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration (0.02N), and you can solve for V2 to find the volume of the 0.1N H2SO4 to be diluted with water to get 0.02N H2SO4.
To calculate the amount of sulfur in 147 g of H2SO4, you need to consider the molar mass of sulfur in the compound. The molar mass of sulfur in H2SO4 is 32 g/mol. Therefore, in 147 g of H2SO4, there would be 32 g of sulfur.
The balanced chemical equation for the reaction between NaOH and H2SO4 is 2NaOH + H2SO4 ⟶ Na2SO4 + 2H2O. From the equation, it is a 1:1 ratio of NaOH to H2SO4. Therefore, to neutralize 10.00 ml of 0.526 M H2SO4, you will need the same amount of 0.526 M NaOH, which is 10.00 ml.
how 2.5N H2SO4 prepared from concentrated H2SO4
The average price for a slave, was around sixpence, the equivalent today of about £3, a very small amount
To prepare a 0.005 M solution of H2SO4 with pH 4, you can first calculate the concentration of H+ ions needed to achieve a pH of 4. Then, use the dissociation of H2SO4 to determine the amount of H2SO4 needed to provide that concentration of H+ ions. Finally, dilute the calculated amount of H2SO4 with water to reach the desired volume of the solution.
To prepare 0.02N H2SO4 from 0.1N H2SO4, you can dilute the 0.1N H2SO4 by adding a calculated amount of water. To calculate the dilution factor, you can use the formula: C1V1 = C2V2, where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration (0.02N), and you can solve for V2 to find the volume of the 0.1N H2SO4 to be diluted with water to get 0.02N H2SO4.
To calculate the amount of sulfur in 147 g of H2SO4, you need to consider the molar mass of sulfur in the compound. The molar mass of sulfur in H2SO4 is 32 g/mol. Therefore, in 147 g of H2SO4, there would be 32 g of sulfur.
Yes, but I do not know the amount.
The balanced chemical equation for the reaction between NaOH and H2SO4 is 2NaOH + H2SO4 ⟶ Na2SO4 + 2H2O. From the equation, it is a 1:1 ratio of NaOH to H2SO4. Therefore, to neutralize 10.00 ml of 0.526 M H2SO4, you will need the same amount of 0.526 M NaOH, which is 10.00 ml.
how 2.5N H2SO4 prepared from concentrated H2SO4
To prepare 1N H2SO4 from 95% H2SO4, you would first need to dilute the 95% H2SO4 with water by adding the appropriate amount of water to achieve the desired concentration. To calculate the volume of 95% H2SO4 needed to make 1N solution, you need to use the formula: (Normality of stock solution) * (Volume of stock solution) = (Normality of diluted solution) * (Volume of diluted solution). Adjust the volumes accordingly to prepare the desired 1N solution.
9.62 Mol H2SO4 ( 6.022 X 10^23/1mol H2SO4 ) = 5.79 X 10^24 molecules of H2SO4
The ratio of H2SO4 to WHAT!
Start with 1 dm^3 (1 Liter) of pure H2O. Molarity is defined as Mol/dm^3, so this is generally an easy way to go. Measure out 3 mol of H2SO4 -> First find the molar weight of Sulfuric acid, which is, according to Google: 98.079g/mol. So 3 mol * 98.079g/mol = 294.24 grams of H2SO4. Add that to 1 Liter of water, and you'll have an aqueous 3 Molar solution!
H2SO4 is sulfuric acid