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The Combined Gas Law relates pressure (P), volume (V) and temperature (T). The appropriate SI units are P in atm, V in liters, and T in degrees Kelvin. The Combined Gas Law equation is (P1*V1)/T1 = (P2V2)/T2. Isolating for V2 the equation then becomes (P1V1T2)/(T1P2) = V2

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How is the combined gas law modified to form the ideal gas law?

The combined gas law deals with pressure, temperature, and volume. If you are given all three and then you are asked to find a variable in different conditions, then use the combined gas law.However, if you are given or are trying to find moles, then use the ideal gas law.


What is combined gas law formula?

The combined gas law combines the three gas laws: Charles' Law, Boyle's Law and Gay-Lussac's Law. It states the ratio of the product of pressure and volume and the absolute temperature of a gas is equal to a constant.


What equation represents the combined gas law?

The combined gas law is represented by the equation [ P_1V_1/T_1 = P_2V_2/T_2, ] where (P) represents pressure, (V) is volume, and (T) is temperature. This equation shows the relationship between pressure, volume, and temperature of a gas when they change.


What two variables must remain constant when testing Charles's law?

Well, pressure has to be kept constant and so does the mass of the gas with Charles's Law. Charles's Law--V1/T1=V2/T2--can be derived from the Combined Gas Law--V1xP1/T1=V2xP2/T2--by keeping the pressure constant which in turn cancels out the pressure in the Combined Gas Law leaving you with Charles's Law. Hope that helps you!


Gas stored in a tank at 273 K has a pressure of 388 kPa. The safe limit for the pressure is 825 kPa. At what temperature will the gas reach this pressure?

Using the combined gas law (P1/T1 = P2/T2), we can calculate the new temperature at the safe limit pressure: (388 kPa / 273 K) = (825 kPa / T2) T2 = 273 K * (825 kPa / 388 kPa) T2 = 578 K Therefore, the gas will reach a pressure of 825 kPa at a temperature of 578 K.

Related Questions

Which equation represent combined gas law?

The general representation of the combined gas law is P1V1/T1 = P2V2/T2


What is the name of the gas law relating pressure and temperature What does it state?

The law relating all three is known as the Combined Gas Law, and follows the formula V1P1/T1=V2P2/T2.


What variables stay the same in Charles law?

Well, pressure has to be kept constant and so does the mass of the gas with Charles's Law. Charles's Law--V1/T1=V2/T2--can be derived from the Combined Gas Law--V1xP1/T1=V2xP2/T2--by keeping the pressure constant which in turn cancels out the pressure in the Combined Gas Law leaving you with Charles's Law.


What are the gas laws?

Boyle' Law P1V1 = P2V2 Charles' Law V1 / T1 = V2 / T2 Gay-Lussac's Law P1 ÷ T1 = P2 ÷ T2 The Combined Gas LawP1V1 / T1 = P2V2 / T2 The Ideal Gas Law PV=nRT KEY: P = pressure V = volume T = temperature R = 0.0821atm*L/mol*K n = number of mole of gas


How is the combined gas law modified to form the ideal gas law?

The combined gas law deals with pressure, temperature, and volume. If you are given all three and then you are asked to find a variable in different conditions, then use the combined gas law.However, if you are given or are trying to find moles, then use the ideal gas law.


What is combined gas law formula?

The combined gas law combines the three gas laws: Charles' Law, Boyle's Law and Gay-Lussac's Law. It states the ratio of the product of pressure and volume and the absolute temperature of a gas is equal to a constant.


What equation represents the combined gas law?

The combined gas law is represented by the equation [ P_1V_1/T_1 = P_2V_2/T_2, ] where (P) represents pressure, (V) is volume, and (T) is temperature. This equation shows the relationship between pressure, volume, and temperature of a gas when they change.


What two variables must remain constant when testing Charles's law?

Well, pressure has to be kept constant and so does the mass of the gas with Charles's Law. Charles's Law--V1/T1=V2/T2--can be derived from the Combined Gas Law--V1xP1/T1=V2xP2/T2--by keeping the pressure constant which in turn cancels out the pressure in the Combined Gas Law leaving you with Charles's Law. Hope that helps you!


Gas stored in a tank at 273 K has a pressure of 388 kPa. The safe limit for the pressure is 825 kPa. At what temperature will the gas reach this pressure?

Using the combined gas law (P1/T1 = P2/T2), we can calculate the new temperature at the safe limit pressure: (388 kPa / 273 K) = (825 kPa / T2) T2 = 273 K * (825 kPa / 388 kPa) T2 = 578 K Therefore, the gas will reach a pressure of 825 kPa at a temperature of 578 K.


What is the origvol of gas if the gas press is 135kpa with a temp of 295a gas volume of 575l a press of 105ka temp of270k?

To find the original volume of gas, you can use the combined gas law equation: (P1V1)/T1 = (P2V2)/T2. Plug in the given values to solve for the original volume, where P1 = 135 kPa, V1 = 575 L, T1 = 295 K, P2 = 105 kPa, and T2 = 270 K. Solving for V1 will give you the original volume of the gas.


A sample of nitrogen gas is stored in a 500.0ml flask at 108kpa and 10.0c the gas is transferred to a 750.0ml flask at 21.0c what is the pressure of nitrogen in the second flask?

To find the pressure of the nitrogen gas in the second flask, you can use the combined gas law equation: P1V1/T1 = P2V2/T2, where P1, V1, and T1 are the initial pressure, volume, and temperature, and P2, V2, and T2 are the final pressure, volume, and temperature. Plug in the given values to find the final pressure of nitrogen in the second flask.


A sample of air has a volume of 140ml at 67degrees Celsius At what temperature will its volume be 50ml at constant pressure?

V1/T1 = V2/T2 Where temperature must be in Kelvins 67C + 273 = 340 K So 140/340 = 50/T2 Find T2 340/140(50) = T2 T2 = 121 K or -152C