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At a certain temperature a 0.25 M solution of HF has a pH of 2.3 What is the Ka of HF at this temperature?
To find the Ka of HF at this temperature, you can use the formula pH = pKa + log([A-]/[HA]). Since HF is a weak acid, [A-] is equal to [H+], so you can substitute [H+] for [A-] in the formula. Rearrange the formula to solve for pKa. Then convert pKa to Ka using the relationship: Ka = 10^(-pKa).
What is the pka of an acid whose ka is 6.510-6?
The pKa of an acid is calculated by taking the negative logarithm (base 10) of the acid dissociation constant (Ka). In this case, the pKa would be approximately 5.19.
What is the pka of .012M solution and a pH of 2.31?
HA ==> H+ + A-Ka = [H+][A-][HA] and from pH = 2.31, calculated [H+] = 4.89x10^-3 M Ka = (4.89x10^-3)(4.89x10^-3)/0.012 Ka = 1.99x10^-3 pKa = 2.70
How do you use pka to find the pH value?
PKa = -log Ka so if you multiply across by -1 and then taking the antilog you can get Ka Ka.Kb = Kw where Kw = 1.0 x 10^14 PKa + PKb = PKw = 14 that should give you a start.
How do you calculation pH from ka?
pH = pKa + log([A-]/[HA]) pH = pKa+log([conjugate base]/[undissociated acid]) pKa is also a measure of the strength of an acid. A low pKa is a strong acid, a higher pKa is a weak acid.
What is ka of pka OF 10.26?
The pKa value is the negative logarithm of the acid dissociation constant (Ka). To find Ka from pKa, you can use the formula ( Ka = 10^{-\text{pKa}} ). For a pKa of 10.26, the calculation would be ( Ka = 10^{-10.26} ), which is approximately ( 5.5 \times 10^{-11} ). Thus, the Ka corresponding to a pKa of 10.26 is about ( 5.5 \times 10^{-11} ).
What is the Ka for aspirin with a pka of 3.48?
All you need to do to get Ka is to take the antilog of the pKa.
What is Henderson-Hasselbalch equation?
Its an equation you can use to find the pH of a solution. it is.... --- pH = pKa + log (Base/Acid) --- these may help too Ka = 10^-pKa Kw = Ka*Kb
An unknown acid has a pKa 5.11. Determine the Ka for the acid.?
pKa = -log Ka and thus Ka = 10^-pKaKa = antilog pKaKa = 7.76x10^-6
At a certain temperature a 0.25 M solution of HF has a pH of 2.3 What is the Ka of HF at this temperature?
To find the Ka of HF at this temperature, you can use the formula pH = pKa + log([A-]/[HA]). Since HF is a weak acid, [A-] is equal to [H+], so you can substitute [H+] for [A-] in the formula. Rearrange the formula to solve for pKa. Then convert pKa to Ka using the relationship: Ka = 10^(-pKa).
The Ka of an unknown weak acid is 5.4 x 10 to the power of negative 10. Determine the pKa of the weak acid?
pKa = -log KapKa = -log 5.4x10^-10pKa = 9.27
What is the pka of an acid whose ka is 6.510-6?
The pKa of an acid is calculated by taking the negative logarithm (base 10) of the acid dissociation constant (Ka). In this case, the pKa would be approximately 5.19.
What is pKa in chemistry?
It refers to the acidity of the fatty acid (which make up the oils). Every fatty acid is composed of a non-polar long chain of hydrocarbons (carbon and hydrogen) and a polar head made up of Carboxylic ACID. Every acid has something called pKa which determines the acidity of that acid.The bigger the pKa (e.g. 25), the weaker the acid.The smaller ther pKa (e.g. 2), the stronger the acid.
What is the pka of .012M solution and a pH of 2.31?
HA ==> H+ + A-Ka = [H+][A-][HA] and from pH = 2.31, calculated [H+] = 4.89x10^-3 M Ka = (4.89x10^-3)(4.89x10^-3)/0.012 Ka = 1.99x10^-3 pKa = 2.70
How do you use pka to find the pH value?
PKa = -log Ka so if you multiply across by -1 and then taking the antilog you can get Ka Ka.Kb = Kw where Kw = 1.0 x 10^14 PKa + PKb = PKw = 14 that should give you a start.
How do you calculation pH from ka?
pH = pKa + log([A-]/[HA]) pH = pKa+log([conjugate base]/[undissociated acid]) pKa is also a measure of the strength of an acid. A low pKa is a strong acid, a higher pKa is a weak acid.
What is the pKa value for sodium octanesulfonate?
The pKa value for sodium octanesulfonate is typically around 2.0 to 2.5.
