The pKa value is the negative logarithm of the acid dissociation constant (Ka). To find Ka from pKa, you can use the formula ( Ka = 10^{-\text{pKa}} ). For a pKa of 10.26, the calculation would be ( Ka = 10^{-10.26} ), which is approximately ( 5.5 \times 10^{-11} ). Thus, the Ka corresponding to a pKa of 10.26 is about ( 5.5 \times 10^{-11} ).
The ratio of 38 to 1026 is 1:27. To find the ratio, you divide both numbers by their greatest common factor, which in this case is 2. So, 38 ÷ 2 = 19 and 1026 ÷ 2 = 513. Therefore, the ratio of 38 to 1026 is 19:513 or simplified to 1:27.
The LCM is 7182.
Ka has an "a" k does not
Jadoo Ka Charagh was created in 1995.
Muqaddar Ka Faisla was created in 1987.
All you need to do to get Ka is to take the antilog of the pKa.
To find the pKa from Ka, you take the negative logarithm (base 10) of the Ka value. The formula is pKa = -log(Ka). This conversion helps simplify comparisons of acid strength.
pKa = -log Ka and thus Ka = 10^-pKaKa = antilog pKaKa = 7.76x10^-6
pKa = -log KapKa = -log 5.4x10^-10pKa = 9.27
The pKa of an acid is calculated by taking the negative logarithm (base 10) of the acid dissociation constant (Ka). In this case, the pKa would be approximately 5.19.
It refers to the acidity of the fatty acid (which make up the oils). Every fatty acid is composed of a non-polar long chain of hydrocarbons (carbon and hydrogen) and a polar head made up of Carboxylic ACID. Every acid has something called pKa which determines the acidity of that acid.The bigger the pKa (e.g. 25), the weaker the acid.The smaller ther pKa (e.g. 2), the stronger the acid.
HA ==> H+ + A-Ka = [H+][A-][HA] and from pH = 2.31, calculated [H+] = 4.89x10^-3 M Ka = (4.89x10^-3)(4.89x10^-3)/0.012 Ka = 1.99x10^-3 pKa = 2.70
To find the Ka of HF at this temperature, you can use the formula pH = pKa + log([A-]/[HA]). Since HF is a weak acid, [A-] is equal to [H+], so you can substitute [H+] for [A-] in the formula. Rearrange the formula to solve for pKa. Then convert pKa to Ka using the relationship: Ka = 10^(-pKa).
Its an equation you can use to find the pH of a solution. it is.... --- pH = pKa + log (Base/Acid) --- these may help too Ka = 10^-pKa Kw = Ka*Kb
HA ==> H+ + A-Ka = [H+][A-][HA] and from pH = 2.31, calculated [H+] = 4.89x10^-3 M Ka = (4.89x10^-3)(4.89x10^-3)/0.012 Ka = 1.99x10^-3 pKa = 2.70
The pKa value for sodium octanesulfonate is typically around 2.0 to 2.5.
No. An acid with a large Ka is stronger. A lower pKa indicates a stronger acid.