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What is the ratio of 38 and 1026?
It is in the ratio of: 1 to 27
What is the LCM of 38 27 21?
The LCM is 7182.
What is the relationship between K and Ka?
Ka has an "a" k does not
When was Muqaddar Ka Faisla created?
Muqaddar Ka Faisla was created in 1987.
When was Naukar Biwi Ka created?
Naukar Biwi Ka was created in 1983.
What is the Ka for aspirin with a pka of 3.48?
All you need to do to get Ka is to take the antilog of the pKa.
An unknown acid has a pKa 5.11. Determine the Ka for the acid.?
pKa = -log Ka and thus Ka = 10^-pKaKa = antilog pKaKa = 7.76x10^-6
What is the Ka for HCl?
The Ka of hydrogen iodide is approx. 1010. The pKa of hydrogen iodide is approx. - 9.
The Ka of an unknown weak acid is 5.4 x 10 to the power of negative 10. Determine the pKa of the weak acid?
pKa = -log KapKa = -log 5.4x10^-10pKa = 9.27
What is pKa in chemistry?
It refers to the acidity of the fatty acid (which make up the oils). Every fatty acid is composed of a non-polar long chain of hydrocarbons (carbon and hydrogen) and a polar head made up of Carboxylic ACID. Every acid has something called pKa which determines the acidity of that acid.The bigger the pKa (e.g. 25), the weaker the acid.The smaller ther pKa (e.g. 2), the stronger the acid.
How is the KB of ammonia calculated from the half titration point?
At half titration pH=pKa (you need the pH from the graph of your titration, y axis) ph = pKa + log (base/acid) 10^-pKa = Ka Kw=Ka*Kb Kb=Kw/Ka Ka = Kw/Kb
What is the Ka for acetic acid CH3COOH?
The KB value is listed below: pKa + pKb - 14 pKa = -log10 (Ka), Ka of acetic acid = 1.8*10^-5 pKa = 4.74, pkb = 9.255 9.255 = -log10(Kb), Kb = 5.56*10^-10
What is the pKa value for sodium octanesulfonate?
The pKa of sulfonic acid is < 0
What are the numbers of strong acids?
pKa < 0.0 Ka > 1.0
What is the pH of fluorosulfuric acid?
The pKa of the fluorosulfuric acid is -10; HSO3F is a very strong acid, a so-called superacid. Ka is the dissociation constant; pKa is the decimal logarithm of Ka.
How do you use pka to find the pH value?
PKa = -log Ka so if you multiply across by -1 and then taking the antilog you can get Ka Ka.Kb = Kw where Kw = 1.0 x 10^14 PKa + PKb = PKw = 14 that should give you a start.
What is Henderson-Hasselbalch equation?
Its an equation you can use to find the pH of a solution. it is.... --- pH = pKa + log (Base/Acid) --- these may help too Ka = 10^-pKa Kw = Ka*Kb
