0
To make a 0.1 M solution of ammonia hydroxide (NH4OH) using a 25% solution, you would need to dilute the 25% solution. To do this, you can use the formula C1V1 = C2V2, where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration (0.1 M), and V2 is the final volume you want to make. Calculate the volume of the 25% solution needed to achieve a 0.1 M concentration. Then, add water to reach the desired final volume.
What else can I help you with?
What is pH value of 28 percent ammonia solution?
My best guess is about pH = 12 to 12.5, it is a rather concentrated but weak base.
What is the molarity of a solution with a percent concentration of a given solute?
To find the molarity of a solution with a percent concentration of a solute, you need to know the molecular weight of the solute and the density of the solution. Then, you can use the formula: Molarity (percent concentration density) / (molecular weight 100).
Is Parson's ammonia straight or is it a percent of ammonia?
Ammonia is a gas - it can't be "straight".
What is the molarity of 35 per cent Hydrochloric acid solution with specific gravity of 1.8 gram per liter?
To find the molarity, we first need to calculate the weight percent of hydrochloric acid in the solution: 35% of the solution is HCl. Then we calculate the molarity using the specific gravity, which is the ratio of the density of the solution to the density of water. Finally, we use the molarity formula to find the molarity: Molarity = (Weight % HCl / molar mass of HCl) / (Specific gravity of the solution).
How can you determine molarity from percent purity of solution?
Molarity is the no of moles of solute dissolved per litre of a solution. now if u want to find it from the percentage purity , here is the formula for that Molarity = % purity x density x 10 ___________________ molar weight of the solute note : density is usually given %purity problems, if its not u can evualvate it from from formula { d= mass/volume} i hope it solves the problem
A bottle of commercial concentrated aqueous ammonia is labeled 28.89 percent NH3 by mass and density is 0.8960 grams mL. What is the molarity of the ammonia solution?
To find the molarity, first calculate the moles of NH3 in 100g of the solution using the mass percent. Then convert the volume of the solution (1 mL) to liters. Finally, divide moles by liters to obtain the molarity.
What will happen if a small amount of sodium hydroxide is added to a 0.1 M solution of ammonia?
The sodium hydroxide will react with ammonia to form a complex called sodamide and water. This reaction will increase the pH of the solution and result in the formation of a new compound.
What is pH value of 28 percent ammonia solution?
My best guess is about pH = 12 to 12.5, it is a rather concentrated but weak base.
What is the molarity of a solution with a percent concentration of a given solute?
To find the molarity of a solution with a percent concentration of a solute, you need to know the molecular weight of the solute and the density of the solution. Then, you can use the formula: Molarity (percent concentration density) / (molecular weight 100).
Can one solution have a greater concentration than another in terms of weight percent but a lower concentration in terms of Molarity?
Yes, one solution can have a greater concentration in terms of weight percent while having a lower concentration in terms of molarity. Weight percent is based on the mass of solute relative to the total mass of the solution, while molarity is based on the number of moles of solute per liter of solution. If the solute has a high molar mass, a solution can have a high weight percent but a lower molarity compared to another solution with a lower weight percent but a solute of lower molar mass.
How do you prepare 6n ammonium hydroxide from 30 percent solution?
To prepare 6 nM ammonium hydroxide a 30 percent solution you need to know the volume of the 30 percent solution that you have and the volume of 6nM solution you would like to make. Then use the following formula: C1V1 = C2V2 where C = concentration in moles/Liter and V = volume in liters.
The molarity of a 5 percent solution of NH3 in water?
The molarity of a 5% solution of NH3 in water depends on the density and molecular weight of NH3. Without this information, it is not possible to calculate the molarity.
Is Parson's ammonia straight or is it a percent of ammonia?
Ammonia is a gas - it can't be "straight".
What is the molarity of 35 per cent Hydrochloric acid solution with specific gravity of 1.8 gram per liter?
To find the molarity, we first need to calculate the weight percent of hydrochloric acid in the solution: 35% of the solution is HCl. Then we calculate the molarity using the specific gravity, which is the ratio of the density of the solution to the density of water. Finally, we use the molarity formula to find the molarity: Molarity = (Weight % HCl / molar mass of HCl) / (Specific gravity of the solution).
How can you determine molarity from percent purity of solution?
Molarity is the no of moles of solute dissolved per litre of a solution. now if u want to find it from the percentage purity , here is the formula for that Molarity = % purity x density x 10 ___________________ molar weight of the solute note : density is usually given %purity problems, if its not u can evualvate it from from formula { d= mass/volume} i hope it solves the problem
What would be the molarity of a 5 percent NaCl solution?
To calculate the molarity of a 5% NaCl solution, you need to know the density of the solution. Once you have the density, you can convert the percentage to grams per liter. Then, using the molar mass of NaCl (58.44 g/mol), you can calculate the molarity using the formula Molarity = (mass of solute in g) / (molar mass of solute in g/mol) / (volume of solution in L).
How do you find the mass percent mole fraction molality and molarity of a solution?
Mass percent = grams of solute/total grams of solution Mole fraction = mols component/total mols mix. Molarity = mols solute/L solution Molality = mols solute/kg solvent Hope this helps :)
