1M contains 43.1ml in 500ml,
2M contains 86.2ml in 500ml
6g Tris HCl + 100ml dH2O, pH 6.8
No. The heat of reaction for 50mL of each will be multiplied by 2 for 100mL of each since heat of reaction is really on a per mole product basis, and there will be twice as many moles of both HCl and NaOH in 100mL as in 50mL.
10.82
add 50% water to it
The mole fraction of HCl is 0.34.
Preparing 1N HCl for 1L. 1N=1M in HCl. Conc. HCl= 12M M1V1=M2V2 12*V1=1*1000 V1=1000/12 V1=83.33ml 1N HCl= 83.33ml of Conc. HCl in 1L of water 2N HCl= 167ml of Conc. HCl in 1L of water.
6g Tris HCl + 100ml dH2O, pH 6.8
No. The heat of reaction for 50mL of each will be multiplied by 2 for 100mL of each since heat of reaction is really on a per mole product basis, and there will be twice as many moles of both HCl and NaOH in 100mL as in 50mL.
10.82
add 50% water to it
The mole fraction of HCl is 0.34.
Confirmed.
to prepare 100ml of 100mM Trissolution: Mol wt of Tris=121.14121.14g in 1000ml ----> 1M12.11g in 100ml -------->1M1M=1000mM121.1g---->1000mM12.11g ----------->100mM1.211g in 100ml and 100mM Tris
Dilution from stock solution: Ndilution*Vdilution = Nstock*Vstock Vstock = (0.5N*100ml) / 5.0N = 10ml so take 10ml HCl from 5.0N stock solution + 90ml H2O
Not entirely correct: The molecular weight of HCl is 36.46g/Mole therefore a 36% (w/w) solution would be 36g/100g H2O or 36g/100mL H2O or 360g/L dividing that out, an exact 36% soln of HCl would be 9.87M (or 9.87N). To make a 1L soln of 1M HCl from 9.87M HCl you add 101.28ml HCl @ 9.87M to 898.72ml H2O. In practice HCl is labeled 36-38% (w/w) and it is treated as 10M (10N), for an exact measurement one must do a titration for the Cl ion. Add 85ml of 36w/w HCl to 900 ml of water,mix dilute to 1000ml with water,to get 1M HCl
You cannot make HCL out from just Xhlorine. U will need Hydrogen to. Hcl is a Hydrochloric solution so u will need a method to combine Hydroger and chlorine in order to make HCL
The mole fraction of HCl in 20 percent aqueous solution is 0.21.