Oh, dude, it's simple! To make 2M HCl in 100ml from 36% HCl, you'd need to dilute the 36% HCl with water. Just mix 5.56ml of 36% HCl with 94.44ml of water, and voila, you've got yourself some 2M HCl. It's like making a fancy cocktail, but with chemicals!
To prepare 100ml of 0.5N HCl solution, you would need to dilute concentrated HCl (37%) with distilled water in a volumetric flask. Measure 4.2ml of concentrated HCl, add it to the volumetric flask, and then dilute with distilled water to bring the total volume to 100ml. Mix well to ensure uniform concentration.
To make a 1% HCl solution from a 35% HCl solution, you would need to dilute the concentrated solution with water. The ratio of concentrated HCl to water would be approximately 1:34. So, to make 1% HCl, you would mix 1 part of the 35% HCl solution with 34 parts of water.
No, a 38% HCl solution is not the same as a 12N HCl solution. The concentration of a solution is based on the amount of solute dissolved in a specific volume of solvent. A 38% HCl solution means there is 38 grams of HCl in 100 mL of solution, while a 12N HCl solution means there are 12 moles of HCl in one liter of solution.
To make 0.25N HCl from 1.00N HCl, you would need to dilute the 1.00N HCl solution by adding three parts of water for every part of the original solution. For example, you can mix 1 mL of 1.00N HCl with 3 mL of water to obtain 0.25N HCl solution.
To find the mole fraction of HCl in the solution, we first need to calculate the molar mass of HCl (H=1g/mol, Cl=35.5g/mol). Then, determine the number of moles of HCl in 100g of the solution. Finally, calculate the mole fraction of HCl by dividing the moles of HCl by the total moles of solute and solvent in the solution.
To prepare 100ml of 0.5N HCl solution, you would need to dilute concentrated HCl (37%) with distilled water in a volumetric flask. Measure 4.2ml of concentrated HCl, add it to the volumetric flask, and then dilute with distilled water to bring the total volume to 100ml. Mix well to ensure uniform concentration.
To make a 1% HCl solution from a 35% HCl solution, you would need to dilute the concentrated solution with water. The ratio of concentrated HCl to water would be approximately 1:34. So, to make 1% HCl, you would mix 1 part of the 35% HCl solution with 34 parts of water.
Ah, preparing a 0.02 M solution of HCl is a wonderful journey. Simply measure out the correct amount of hydrochloric acid and dilute it with water until you reach the desired concentration. Remember to handle chemicals with care and always wear appropriate safety gear. Happy experimenting, my friend!
Not entirely correct: The molecular weight of HCl is 36.46g/Mole therefore a 36% (w/w) solution would be 36g/100g H2O or 36g/100mL H2O or 360g/L dividing that out, an exact 36% soln of HCl would be 9.87M (or 9.87N). To make a 1L soln of 1M HCl from 9.87M HCl you add 101.28ml HCl @ 9.87M to 898.72ml H2O. In practice HCl is labeled 36-38% (w/w) and it is treated as 10M (10N), for an exact measurement one must do a titration for the Cl ion. Add 85ml of 36w/w HCl to 900 ml of water,mix dilute to 1000ml with water,to get 1M HCl
Let A be the volume of 33% HCl and B the volume of 20% HCl Then, A + B = 5.........so, B = 5 - A And, 33A + 20B = 5 x 30.5 = 152.5 Substituting for B gives :- 33A + 20(5 - A) = 33A + 100 - 20A = 13A + 100 = 152.5 Thus, 13A = 152.5 - 100 = 52.5 : A = 52.5/13 = 4.0385 Litres (4dp) Which means that B = 5 - 4.0385 = 0.9615 Litres Mix 4.0385 Litres of 33% HCL with 0.9615 Litres of20% HCl to get 5 litres of 30.5% HCl.
No, a 38% HCl solution is not the same as a 12N HCl solution. The concentration of a solution is based on the amount of solute dissolved in a specific volume of solvent. A 38% HCl solution means there is 38 grams of HCl in 100 mL of solution, while a 12N HCl solution means there are 12 moles of HCl in one liter of solution.
To make 0.25N HCl from 1.00N HCl, you would need to dilute the 1.00N HCl solution by adding three parts of water for every part of the original solution. For example, you can mix 1 mL of 1.00N HCl with 3 mL of water to obtain 0.25N HCl solution.
To find the mole fraction of HCl in the solution, we first need to calculate the molar mass of HCl (H=1g/mol, Cl=35.5g/mol). Then, determine the number of moles of HCl in 100g of the solution. Finally, calculate the mole fraction of HCl by dividing the moles of HCl by the total moles of solute and solvent in the solution.
To dilute 36M HCl to make 1M HCl, you need to add 1 part of 36M HCl to 36 parts of water. So, for example, if you want to make 1 liter of 1M HCl, you would mix 27.8 ml of 36M HCl with 972.2 ml of water. Always remember to add acid to water slowly and with stirring to prevent splattering.
1 N HCl (hydrochloric acid) is equivalent to a concentration of 0.1 M (molarity), which means it contains 1 mole of HCl per liter of solution. The percentage of HCl in 1 N solution is about 3.65%, calculated based on the molecular weight of HCl.
No. The heat of reaction for 50mL of each will be multiplied by 2 for 100mL of each since heat of reaction is really on a per mole product basis, and there will be twice as many moles of both HCl and NaOH in 100mL as in 50mL.
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