0
Ah, preparing a 0.02 M solution of HCl is a wonderful journey. Simply measure out the correct amount of hydrochloric acid and dilute it with water until you reach the desired concentration. Remember to handle chemicals with care and always wear appropriate safety gear. Happy experimenting, my friend!
What else can I help you with?
How do you prepare 1N Hcl solution Dont tell in gL how much ml is required?
1N HCL is the same as 1 Molar HCl. You take the # of H ions and multiply by the molarity to get the Normality. Usually you buy HCl in concentrated form which is 12 Molar or 12 Normal HCL. You need to dilute the concentrated HCl to get the reduced concentration. Use the formula Molarity Initial x Volume Initial = Molarity Final x Volume Final ex. 12 M HCL x 10 ml = 1 M x 120 ml. So take 10 ml of concentrated HCl and add enough water to make 120 ml. This will give you 120 ml of 1 M (which is 1N) HCl. Venkat Reddy
What is the molarity of the solution produced when 85.6 g of hydrochloric acid HCl is dissolved in sufficient water to prepare 0.385 L of solution?
To find the molarity, first calculate the number of moles of HCl present: 85.6 g / 36.46 g/mol = 2.35 mol Then, divide the moles by the volume in liters: Molarity = 2.35 mol / 0.385 L ≈ 6.10 M. Thus, the molarity of the solution is approximately 6.10 M.
Prepare 500ml of 0.12N HCL solution?
To prepare 500ml of 0.12N HCl solution, you will need to dilute a concentrated hydrochloric acid solution. To do this, measure out 2.5ml of concentrated HCl (37% w/w) and dilute it to 500ml with distilled water. Be sure to wear appropriate safety equipment and handle the acid with caution.
What volume of stock solution would be required to make a 150 mL solution of 0.50 M HCl from a 2.00 M HCl stock solution?
To find the volume of the 2.00 M HCl stock solution needed, we use the formula M1V1 = M2V2. Rearranging for V1 gives us V1 = (M2 * V2) / M1, where M2 is the desired concentration (0.50 M), V2 is the final volume (150 mL), and M1 is the stock concentration (2.00 M). Plugging in the values gives V1 = (0.50 M * 150 mL) / 2.00 M = 37.5 mL. You will need 37.5 mL of the 2.00 M HCl stock solution to make a 150 mL solution of 0.50 M HCl.
How many moles of HCl are consumed in a reaction of 25 mL of 4 M is added to excess CaCO3?
Just multiply 25 mL and 4.0 M but convert 25 mL to liter making it 0.025 L. 0.025 L * 4 M = 0.1 moles
How many ml of 6.00m hcl are needed to prepare 1000 ml of a 100m hcl?
100 M HCl don't exist.
How to prepare 3 M methanolic HCL?
make sure to sudy it alot
What volume of 3.0 M HCl sould be obtained to prepare 100 mL of 1.0 M HCL?
To prepare 100 mL of 1.0 M HCl from a 3.0 M stock solution, you can use the formula: (M_1V_1 = M_2V_2). Solving for V1: (3.0 M)(V1 mL) = (1.0 M)(100 mL), thus V1 = 33.3 mL. So, you would need to measure out 33.3 mL of the 3.0 M HCl solution and then dilute it to 100 mL to obtain 1.0 M HCl.
What volume of a 1.50 M HCl solution should you use to prepare 2.00 L of a 0.100 M HCl solution?
To prepare a 0.100 M HCl solution from a 1.50 M HCl solution, you need to use the dilution formula, which is M1V1 = M2V2. You would need to use (V_1 = \frac{M_2V_2}{M_1}) to calculate the volume needed. Plugging in the values, you would need to use ( V_1 = \frac{0.100 M \times 2.00 L}{1.50 M} = 0.133 L or 133 mL) of the 1.50 M HCl solution.
How to prepare HCL solution?
To prepare a hydrochloric acid (HCl) solution, you can dilute concentrated hydrochloric acid with water. Always add the acid to water slowly while stirring, never add water to acid, as it can cause splattering. Be sure to wear appropriate protective gear and work in a well-ventilated area when handling HCl.
How do you prepare a 0.0001 M soulution HCL using 0.1 M of HCl?
you need to make 1000 times dilutions, this could be done in multi-steps: transfer 1 ml 0.1 M HCl into 100 ml volumetric flask and complete volume with water --------(1) from solution (1) transfer 2 ml into 20 ml volumetric falsk and complete volume with water, this is 0.0001 M HCL.
What volume of 25 M HCl must be diluted to prepare 1.5 L of 4.1x10-2 M HCl?
Use the formula M1V1 = M2 V2 25 M X V1 = [4.1 x 10 -2 ]M x 1.5 L V1 = [4.1 x10-2 x 1.5] / 25 V1 = 0.00246 L = 2.5 mL Take 2.5 mL of 25 M HCl and put it in a analytical measuring flask and complete the rest volume with distilled water (until the total volume is 1500 mL).
Why you use 85 ml Conc HCl for 1 M HCl?
To prepare 1 M hydrochloric acid (HCl) solution, you usually need to dilute concentrated HCl solution (~35-37% HCl) with water in a specific ratio. The specific volume of concentrated HCl needed depends on its concentration and the final volume of the 1 M solution you want to make. In this case, 85 ml of concentrated HCl is likely to be the volume needed to make 1 L of 1 M HCl solution.
How many mL of HCL do you measure to prepare a liter of 0.5N HCL?
44.5 ml HCl TAKE AND DILUTE UP TO 1000 ML WATER MAKE A 0.5 M HCl SOLUTION
How would one prepare 10 ml of a 25 M HCI solution if 1 M HCI was available?
To prepare a 10 ml of a 25 M HCl solution, you would need to dilute the 1 M HCl solution by a factor of 25. You will need 0.25 ml of the 1 M HCl solution and 9.75 ml of solvent (usually water) to make a total volume of 10 ml for the 25 M HCl solution.
How would you prepare 17.2 L of a 3.8 M HCl solution?
First get moles HCl, then get the grams HCl.Molarity = moles of solute/Liters of solution3.8 M HCl = X moles/17.2 Liters= 65.36 moles HCl===============so,65.36 moles HCl (36.458 grams/1 mole HCl)= 2382.89 grams HCl======================and,put this amount, 2382.89 grams, 65.36 moles HCl into the 17.2 liters of solution ( water, I suppose ) 2382.89 grams = 2.38 kilograms. I suppose you could weigh out the HCl in a flask of some sort.
How do you prepare 1000 ml 1 M hydrochloric acid solution from concentrated hydrochloric acid?
To prepare 1000 mL of 1 M HCl solution from concentrated HCl (typically 37% w/w), you would need to dilute 88 mL of concentrated HCl with distilled water to reach the 1000 mL mark. This is because the concentrated HCl is about 12 M. Be sure to add the acid slowly to water while stirring, and always handle concentrated acids with caution due to their corrosive nature.
