make sure to sudy it alot
To prepare 0.1M methanolic HCl, you would first need to calculate the volume of concentrated HCl needed to make the solution. Since methanol is the solvent, you would mix the calculated volume of concentrated HCl with methanol in a volumetric flask and dilute to the desired final volume. It is important to handle concentrated HCl with care due to its corrosive nature and always add acid to solvent, not the other way around, to avoid splattering.
100 M HCl don't exist.
To prepare 100 mL of 1.0 M HCl from a 3.0 M stock solution, you can use the formula: (M_1V_1 = M_2V_2). Solving for V1: (3.0 M)(V1 mL) = (1.0 M)(100 mL), thus V1 = 33.3 mL. So, you would need to measure out 33.3 mL of the 3.0 M HCl solution and then dilute it to 100 mL to obtain 1.0 M HCl.
To prepare a 0.100 M HCl solution from a 1.50 M HCl solution, you need to use the dilution formula, which is M1V1 = M2V2. You would need to use (V_1 = \frac{M_2V_2}{M_1}) to calculate the volume needed. Plugging in the values, you would need to use ( V_1 = \frac{0.100 M \times 2.00 L}{1.50 M} = 0.133 L or 133 mL) of the 1.50 M HCl solution.
To prepare a hydrochloric acid (HCl) solution, you can dilute concentrated hydrochloric acid with water. Always add the acid to water slowly while stirring, never add water to acid, as it can cause splattering. Be sure to wear appropriate protective gear and work in a well-ventilated area when handling HCl.
you need to make 1000 times dilutions, this could be done in multi-steps: transfer 1 ml 0.1 M HCl into 100 ml volumetric flask and complete volume with water --------(1) from solution (1) transfer 2 ml into 20 ml volumetric falsk and complete volume with water, this is 0.0001 M HCL.
Use the formula M1V1 = M2 V2 25 M X V1 = [4.1 x 10 -2 ]M x 1.5 L V1 = [4.1 x10-2 x 1.5] / 25 V1 = 0.00246 L = 2.5 mL Take 2.5 mL of 25 M HCl and put it in a analytical measuring flask and complete the rest volume with distilled water (until the total volume is 1500 mL).
To prepare 1 M hydrochloric acid (HCl) solution, you usually need to dilute concentrated HCl solution (~35-37% HCl) with water in a specific ratio. The specific volume of concentrated HCl needed depends on its concentration and the final volume of the 1 M solution you want to make. In this case, 85 ml of concentrated HCl is likely to be the volume needed to make 1 L of 1 M HCl solution.
To prepare a 10 ml of a 25 M HCl solution, you would need to dilute the 1 M HCl solution by a factor of 25. You will need 0.25 ml of the 1 M HCl solution and 9.75 ml of solvent (usually water) to make a total volume of 10 ml for the 25 M HCl solution.
44.5 ml HCl TAKE AND DILUTE UP TO 1000 ML WATER MAKE A 0.5 M HCl SOLUTION
Ah, preparing a 0.02 M solution of HCl is a wonderful journey. Simply measure out the correct amount of hydrochloric acid and dilute it with water until you reach the desired concentration. Remember to handle chemicals with care and always wear appropriate safety gear. Happy experimenting, my friend!
its PH is 3