You will be using the disodium salt of EDTA (M.W. = 372.24 g/mole). It has been dried for 1
day at 80°C to drive off any superficial moisture. Transfer it in desiccator for an hour.
Weigh carefully about 1.95 g of EDTA (record to
the nearest 0.1 mg). Quantitatively transfer this into a 500 mL volumetric flask then add 2-3 mL
of pH 10 ammonia buffer. Fill the flask about halfway to the mark with deionized water and
swirl to dissolve. This process can take up to 15 minutes. Once dissolved, dilute to the mark
and then cap and invert the flask at least 6 times to get a uniform solution. Keep the solution
capped.
This solution is about 0.01M but for an exact value you need Standardization of this solution with Calcium Carbonate standard solution.
Dissolve 2.92 grams edta in one liter distilled water.
The molar mass of edta is 292.24 g mol-1. Molarity is moles of solute divided by liters of solute. To make a 0.01m solution, take 0.01*the molar mass of the substance and dissolve it in one liter of water. So: 0.01*292.24=2.92 grams.
18.61grams of EDTA in 1000 ml distilled water.
from
michael singh
18.6gms dissolved in 1000ml distilled water
To prepare 1 M CaI aqueous solution, dissolve 29.4 g in a total volume of 100 mls, or 294 g in a total volume of 1 liter.
according to http://www.sciencelab.com/ all these.....Dihydrogen Magnesium Ethylenediaminetetraacetate » Edetate Calcium Disodium, FCC» Edetate Disodium Dihydrogen» Edetate Disodium TS» Edetate Disodium, Dihydrate, FCC» Edetate Disodium, Dihydrate, Reagent, ACS» Edetate Disodium, Dihydrate, USP» Edetic Acid, NF» EDTA Disodium, 0.01 M Solution» EDTA Disodium, 0.01 M Solution, w/Magnesium» EDTA Disodium, 0.05 M Solution» EDTA Disodium, 0.0575 M Solution» EDTA Disodium, 0.1 M Solution» EDTA Disodium, 0.5 M Solution» EDTA Disodium, 10% (w/v) Solution» EDTA Disodium, 2.5% (w/v) Aqueous Solution» EDTA Stabilizer Solution, 500 g/L» Ethylenediaminetetraacetate Acid Diammonium Dihydrogen Salt» Ethylenediaminetetraacetic Acid Calcium Disodium Salt» Ethylenediaminetetraacetic Acid Copper (II) Disodium Salt» Ethylenediaminetetraacetic Acid Dicalcium Salt» Ethylenediaminetetraacetic Acid Dimagnesium Salt» Ethylenediaminetetraacetic Acid Dipotassium Salt, Reagent» Ethylenediaminetetraacetic Acid Iron (III) Ammonium Salt, Solution» Ethylenediaminetetraacetic Acid Magnesium Disodium Salt» Ethylenediaminetetraacetic Acid Tetrasodium Salt, Reagent» Ethylenediaminetetraacetic Acid Tetrasodium Salt, Solution» Ethylenediaminetetraacetic Acid Tripotassium Salt, Dihydrate» Ethylenediaminetetraacetic Acid Trisodium Salt» Ethylenediaminetetraacetic Acid, Dipotassium Magnesium Salt, Dihydrate, USP» Ethylenediaminetetraacetic Acid, Iron (III) Sodium Salt» Ethylenediaminetetraacetic Acid, Powder, Reagent, ACS» Magnesium EDTA, 0.02% (w/v) Solutionhope this was helpful
10-4
You prepare a solution by dissolving a known mass of solute into a specific amount of solvent. In solutions, M is the molarity, or moles of solute per liter of solution. For 300 ml of a 0.1 M Na CL solution from a solid Na CL solution and water you need water and sodium chloride.
5mM = 0.005 moles 100 mL = 0.1 Liters Molarity = moles of solute/Liters of solution 0.005 M EDTA = X moles/0.1 Liters = 0.0005 moles EDTA =_____________ Now, look up the molecular formula for EDTA and find how many grams needed to add to your 100 mL.
18.6gms dissolved in 1000ml distilled water
1 mole EDTA has 4 equivalents. 0.01 N EDTA = 0.01 equivalents/liter, so you need 0.01/4 = 0.0025 moles EDTA/liter.
3.00 M
To prepare 1 M CaI aqueous solution, dissolve 29.4 g in a total volume of 100 mls, or 294 g in a total volume of 1 liter.
It's simple to dilute a solution, just add more water. If you have one liter of 6 molar solution, and add another 5 liters of water, it becomes a 1 molar solution. You can also use M1V1 = M2V2 formula for dilution. For example, if you want to prepare 1 M of solution in 1 litre of water, then how much volume you need from the initial 6 M solution? Simply use the equation, (6 M) x (V1) = (1 M) x (1 litre) ---> V1 = (1 M) x (1 litre)/(6 M) = 0.167 L or 167 ml
according to http://www.sciencelab.com/ all these.....Dihydrogen Magnesium Ethylenediaminetetraacetate » Edetate Calcium Disodium, FCC» Edetate Disodium Dihydrogen» Edetate Disodium TS» Edetate Disodium, Dihydrate, FCC» Edetate Disodium, Dihydrate, Reagent, ACS» Edetate Disodium, Dihydrate, USP» Edetic Acid, NF» EDTA Disodium, 0.01 M Solution» EDTA Disodium, 0.01 M Solution, w/Magnesium» EDTA Disodium, 0.05 M Solution» EDTA Disodium, 0.0575 M Solution» EDTA Disodium, 0.1 M Solution» EDTA Disodium, 0.5 M Solution» EDTA Disodium, 10% (w/v) Solution» EDTA Disodium, 2.5% (w/v) Aqueous Solution» EDTA Stabilizer Solution, 500 g/L» Ethylenediaminetetraacetate Acid Diammonium Dihydrogen Salt» Ethylenediaminetetraacetic Acid Calcium Disodium Salt» Ethylenediaminetetraacetic Acid Copper (II) Disodium Salt» Ethylenediaminetetraacetic Acid Dicalcium Salt» Ethylenediaminetetraacetic Acid Dimagnesium Salt» Ethylenediaminetetraacetic Acid Dipotassium Salt, Reagent» Ethylenediaminetetraacetic Acid Iron (III) Ammonium Salt, Solution» Ethylenediaminetetraacetic Acid Magnesium Disodium Salt» Ethylenediaminetetraacetic Acid Tetrasodium Salt, Reagent» Ethylenediaminetetraacetic Acid Tetrasodium Salt, Solution» Ethylenediaminetetraacetic Acid Tripotassium Salt, Dihydrate» Ethylenediaminetetraacetic Acid Trisodium Salt» Ethylenediaminetetraacetic Acid, Dipotassium Magnesium Salt, Dihydrate, USP» Ethylenediaminetetraacetic Acid, Iron (III) Sodium Salt» Ethylenediaminetetraacetic Acid, Powder, Reagent, ACS» Magnesium EDTA, 0.02% (w/v) Solutionhope this was helpful
use the equation that is standard: 1000 ml 1 M solution= (MOLECULAR WEIGHT) X ml 0.05 M solution = ((MOLECULAR WEIGHT)*X*0.05)/1000
10-4
impossible....u want to use a low contrated solution to dilute into a higher contration solution? No way man,...
49.6 mL
Prepare HCl 1 M by HCl concentration 37 % HCl concentration 37 % have density =1.19 g/ml HCl 1 M use HCl 37 % 82.81 ml make volume with water to 1 liter